Https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6th/v/calculating-interquartile-range-iqr
This is a link that I gave to my little sister that helped her understand what interquartile range is. It has an example as well! I hope this helps!
You made the choice to choose the letter A, a second time.
Answer:
12% of 60, 400% of 18, 55% of 220
Step-by-step explanation:
12% of 60 =7.2
55% of 220 = 121
400% of 18 = 72
7.2, 72, 121
12% of 130 is 15.6 hope it helps!
Answer:
Step-by-step explanation:
Speed = distance travelled/time
A horse ran 800 m in 40 seconds. This means that the speed is
800/40 = 20 m/s
The horse ran 1200 m in 60 seconds. This means that the speed is
1200/60 = 20 m/s
The horse ran 1200 m in 60 seconds. This means that the speed is
480/24 = 20 m/s
Since the horse's rate or speed is the same at each scenario, it means that the relationship between the distance covered by the horse and the time taken is proportional.
Let k represent the constant of proportionality. The constant of proportionality is 20. It represents speed of the horse.
Let d represent the distance in meters.
Let t represent the time in seconds.
Therefore
d = 20t
