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gulaghasi [49]
3 years ago
9

A square has sides that are 80 ft long. Which equations can be used to calculate d the length of a diagonal of the square in fee

t

Mathematics
1 answer:
LenKa [72]3 years ago
7 0
Notice the picture below

just use the pythagorean theorem to ge the diagonal

\bf c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}

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PLEASE ANSWER!!!!! I WILL MARK YOU AS BRAINLIEST!!!!! IT IS HIGHLY APPRECIATED!!! :)
kkurt [141]

Answer:

A number less than 4 was rolled 18 times.

The number cube was rolled 50 times. The relative frequency of rolling a number less than 4 is 36%.

3 0
3 years ago
If the product of six tenths and three tenths is subtracted from the sum of two tenths and four tenths, what
MakcuM [25]

Answer:

-\frac{1}{200}

Step-by-step explanation:

\frac{6}{10}×\frac{3}{10}-\frac{2}{10}+\frac{4}{10}

\frac{6}{10}×\frac{3}{10}=\frac{18}{100}

\frac{18}{100}-\frac{2}{10}=-\frac{1}{50}

-\frac{1}{50}+\frac{4}{10}=\frac{1}{200}

5 0
3 years ago
Fifteen million four hundred and ten thousand five hundred<br>and sixty eight with commas​
Alinara [238K]
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7 0
2 years ago
Read 2 more answers
the area of a rectangle garden is 38 1/4 square meters.The width of the garden is 4 1/2 meters.Find the length of the garden.
never [62]
Area = 38 1/4 = 153/4

Width = 4 1/2 = 9/2

Area = Length x Width

Length = Area/Width

So divide both of them:
\sf{ \frac{153}{4} \div \frac{9}{2} =\sf{ \frac{153}{4} \times \frac{2}{9} = \frac{9 \times 17}{2\times 2}\times \frac{2}{9} = \frac{17}{2}

So the length is equal to \boxed{\sf{\frac{17}{2}}}

4 0
3 years ago
Solve (16×^3-3×^2+43×-5)÷(×^2-2)
Oksana_A [137]

Answer:

3872/(x^2 - 2)

Step-by-step explanation:

Simplify the following:

(16^3 - 3^2 - 5×43)/(x^2 - 2)

3^2 = 9:

(16^3 - 9 - 5×43)/(x^2 - 2)

16^3 = 16×16^2:

(16×16^2 - 9 - 5×43)/(x^2 - 2)

| 1 | 6

× | 1 | 6

| 9 | 6

1 | 6 | 0

2 | 5 | 6:

(16×256 - 9 - 5×43)/(x^2 - 2)

16×256 = 4096:

(4096 - 9 - 5×43)/(x^2 - 2)

43 (-5) = -215:

(4096 - 9 + -215)/(x^2 - 2)

4096 - 9 - 215 = 3872:

Answer: 3872/(x^2 - 2)

7 0
3 years ago
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