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gulaghasi [49]
2 years ago
13

Another find the x Help is appreciated/will give brainliest

Mathematics
1 answer:
viktelen [127]2 years ago
8 0

Step-by-step explanation:

cos x = 3 ÷ 12

cos x = 0.25

x = cos inverse 0.25

x = 75.52°

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There are 220 tickets to a school's annual awards banquet. Each adult ticket, a, cost $25 in each student ticket, s, cost $15 ev
aleksley [76]

Answer:

x + y = 220

25 x + 15 y =  4650

The above system can be used to find the number of adult and student tickets sold.

Step-by-step explanation:

Let us assume the number of Adult's ticket sold = x

And The number of student's tickets sold = y

Now, total number of tickets sold = 220

⇒ x + y = 220

Cost of 1 adult Ticket  = $ 25

⇒ Cost of x adult tickets =  x ( $25) = 25 x

Cost of 1 student Ticket  = $ 15

⇒ Cost of y student tickets =  y ( $15) = 15 x

Also, the total amount made from selling all tickets = $4650

⇒ 25 x + 15 y =  $4650

Here, the given system of equations are:

x + y = 220

and 25 x + 15 y =  4650

The above system can be used to find the number of adult and student tickets sold.

7 0
3 years ago
Write 10 ^ 10 * 10 ^ 0 with a power of 10 with a single exponent using the appropriate exponent rule explain or show your reason
tatiyna

Answer:

10^10

Step-by-step explanation:

Anything to the power of 0 is 1. 10^10 *1 is still 10^10

6 0
3 years ago
Read 2 more answers
30 pts!!!!!!!!!
boyakko [2]
Divide the first one by the second and the answer will be B.
3 0
3 years ago
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0.580000 as a fraction
Paul [167]

Answer:

\frac{58}{100}=\frac{29}{50}

Step-by-step explanation:

Since this is mathematics, significant figures are not necessary.  Thus, we can just take 0.58 and delete the 0s.  Now, 0.58=\frac{58}{100}.

6 0
3 years ago
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krok68 [10]
<span>280 I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself. You can choose 1 of 7 appetizers. So we have n = 7 After that, you chose an entre, so the number of possible meals to this point is n = 7 * 10 = 70 Finally, you finish off with a dessert, so the number of meals is: n = 70 * 4 = 280 Therefore the number of possible meals you can have is 280. Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is n = 77 * 1010 * 44 = 3421880 But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
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