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Leona [35]
3 years ago
11

Which concept is used to prove that the opposite sides of a parallelogram are congruent?

Mathematics
2 answers:
Neko [114]3 years ago
7 0

Answer:

  congruent triangles

Step-by-step explanation:

You can eliminate useless answers based on their wording. "Similar" anything cannot be used to prove congruence. "Rectangles" will not help you prove congruence of parallelogram sides. The only reasonable choice is ...

  congruent triangles

_____

Typically, a diagonal is drawn through the figure, and the two triangles created are shown to be congruent, often by ASA. Then, by CPCTC, sides of the parallelogram are shown to be congruent.

Tresset [83]3 years ago
3 0

Answer: congruent

Step-by-step explanation:

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What are the reasoning for the statement <br><br>6x+6+1=8<br><br>6x+7=8<br><br>6x=1<br><br>X=1/6
AlladinOne [14]
Step 1. Combine like terms
Step 2. Subtract 7 from both sides
Step 3. Divide 6 from both sides
Final answer: x=1/6
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3 years ago
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Solve the given system of equations.<br> - 3a = 36<br> 10a + 3c = 9<br> 2b + 50 = 23
Elodia [21]

Answer:

Solve using the substitution method! Answer down below:)

Step-by-step explanation:

(a,b,c) = ( -12, -27/2,43)

Hope it helps:)

5 0
3 years ago
I am thinking of two numbers. The difference of the two numbers is 36. Their sum is 286. What are the two numbers I am thinking
Diano4ka-milaya [45]
Let's call the two numbers a and b. So we know that the difference of the two numbers is 36:

a - b = 36

And we know that their sum is 286:

a + b = 286

We can use either of these equations to solve for one of the variables in terms of the other variable. Let's use the first and solve for a:

a - b = 36

a = 36 + b

Now we plug this into the other equation and solve for b there:

(36 + b) + b = 286 

36 + 2b = 286

2b = 250

b = 125
6 0
3 years ago
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Two planes that are traveling toward each other are 720 miles apart. One plane is traveling 40 miles per hour faster than the ot
natali 33 [55]

Answer:

y = 460 miles per hr

x = 500 miles per hr

Step-by-step explanation:

Let the planes be X any

Let their speeds be xmiles/hr and ymiles/hr respectively

x = y + 40 (assuming X is faster by 40miles/hr)

Distance travelled by X to meet Y = 0.75x

Distance travelled by Y to meet X = 0.75y

0.75x + 0.75y = 720 --------1

Put x = y + 40 in eqn 1

0.75(y+40) + 0.75y = 720

0.75y + 30 + 0.75y= 720

1.5y = 690

y = 460 miles per hr

x = 460 +40

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7 0
2 years ago
In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=26°, and QO = 4.9 feet. Find the length of PQ to the nearest tenth of a foot.
Step2247 [10]

Given:

In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.

To find:

The measure of side PQ.

Solution:

In ΔOPQ,

m\angle O+m\angle P+m\angle Q=180^\circ        [Angle sum property]

26^\circ+m\angle P+90^\circ=180^\circ

m\angle P+116^\circ=180^\circ

m\angle P=180^\circ -116^\circ

m\angle P=64^\circ

According to Law of Sines, we get

\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}

Using the Law of Sines, we get

\dfrac{p}{\sin P}=\dfrac{o}{\sin O}

\dfrac{QO}{\sin P}=\dfrac{PQ}{\sin O}

Substituting the given values, we get

\dfrac{4.9}{\sin (64^\circ)}=\dfrac{PQ}{\sin (26^\circ)}

\dfrac{4.9}{0.89879}=\dfrac{PQ}{0.43837}

\dfrac{4.9}{0.89879}\times 0.43837=PQ

2.38989=PQ

Approximate the value to the nearest tenth of a foot.

PQ\approx 2.4

Therefore, the length of PQ is 2.4 ft.

4 0
3 years ago
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