75=6w is the answer to that
To determine this, we need to set up fractional proportions.
First, put 12.5% (what we're looking for) over 100%, which is the total (256).
12.5/100 should be your first fraction.
Now, put x over 256, x being 12.5% of 256.
x/256 should be your second fraction.
Now put these two fractions as an equation.
x/256 = 12.5/100
This may be where things get tricky if you don't pay attention.
Cross multiply the top number (numerator) of x/256 with the bottom number (denominator) of 12.5/100.
You should end up with 100x.
Now, cross multiply the top number of 12.5/100 with the bottom number of x/256.
You should end up with 3200.
Now our equation is:
100x = 3200
Divide both sides by 100 to get x.
100x/100 = x
3200/100 = 32
x = 32 is now your simplified equation.
Your final answer is:
32 is 12.5% of 256.
Also, since 12.5% is 1/8 of 100%, we can test our answer.
Multiply 32 by 8 to get 8/8 (100%).
32 x 8 = 256.
Your answer is 32.
I hope this helps!
Answer:
3/4 gallon of purple paint left
Step-by-step explanation:
3/8 + 5/8 =8/8
he uses 2/8 so
8/8 - 2/8 = 6/8
3/4 (simplified)
Answer:
2 real solutions
Step-by-step explanation:
Remember this messy thing?
The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.
For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.
Answer:
The y-intercept is at (0,8), so you can graph that point. Then the slope is -3/5. So the change in y coordinate divide the change in x coordinate is always -3/5. Thus 8-y/0-x=-3/5. You can choose any value for y and x as long as 8-y=-3. And 0-x=5. The point on the graph will just be (x,y) for the values you find.
