The only expressions that are correctly factored are;
A) 16a⁵ - 20a³ = 4a³(4a² - 5)
B) 24a⁴ + 18 = 6(4a⁴ + 3)
C) 12a³ + 8a = 4a(3a² + 2)
D) 30a⁶ - 24a² = 3a²(10a⁴ - 8)
<h3>How to factorize equations?</h3>
1) 16a⁵ - 20a³
To factorize this, we will have to get out the common factor first. The common factor is 4a³. Thus, we now have;
4a³(4a² - 5)
2) 24a⁴ + 18
To factorize this, we will have to get out the common factor first. The common factor is 6. Thus, we now have;
6(4a⁴ + 3)
3) 12a³ + 8a
To factorize this, we will have to get out the common factor first. The common factor is 4a. Thus, we now have;
4a(3a² + 2)
4) 30a⁶ - 24a²
To factorize this, we will have to get out the common factor first. The common factor is 3a². Thus, we now have;
3a²(10a⁴ - 8)
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D.
(0) - 7 < 2(0) - 6
0 - 7 < 0 - 6
-7 < -6
-6 is higher than -7 which makes the inequality true.
Answer:
Step-by-step explanation:
Because the arcs HI and GJ are the same, that means that the segments HI and GJ are also the same. Therefore,
c + 20 = 2c and
20 = c
