Answer:
<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
Number of letters of the word "millennium" = 10
Letters repeated:
m = 2 times
i = 2 times
l = 2 times
n = 2 times
2. The number of different ways that the letters of millennium can be arranged is:
We will use the n! or factorial formula, this way:
10!/2! * 2! * 2! * 2!
(10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)/(2 * 1) * (2 * 1) * (2 * 1) * (2 *1)
3'628,800/2*2*2*2 = 3'628,800/16 = 226,800
<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>
Answer:
C
Step-by-step explanation:
19-8=11.
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
$12 each. $75 - $39 = $36. $36 divided by 3 = $12. Assuming he used all his money.
<span>8/5 = 1.6 bag per minute
8 bags of skittles in 5 minutes
? 10 minutes
8 x 10 / 5
= 80 /5
= 16
answer
</span>1.6 bag per minute
<span>and
16 bags in 10 minutes</span>
