Answer: The second period class has the greater first quartile.
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The best and most correct answer among the choices provided by the question is </span><span>B.False</span>.
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Hope my answer would be a great help for you. </span>
4x^2 -28c + 40 = 1
-28c = 1 -4x^2 -40
-28c = -39 -4x^2
c = 39/28 + 4/28x^2
c = 39/28 + 1/7x^2 => answer
Answer:
A...similar triangles
Step-by-step explanation:
option b... the two triangles are not congruent
option c... the area of ∆AED= 3, ∆ACB= 12.. half of 12 is 6.. wrong
option d. perimeter of ∆AED= 8.60, area of ∆ACB = 12... one fouth of 12 =3. wrong.
option A.. similar triangles have the same shape but they necessarily don't need to have the same size. ... correct! both triangles are right angled triangles.
note.. perimeter is summation of all sides..
solving unknown side use Pythagoras formulae
hyp= √ height (sq) + base (sq)
area of ∆ = 1/2 * base * height...