Answer:
the third option, commensalism
Explanation:
Answer:
0.7
Explanation:
Using Hardy-Weinberg equation of genetic variation being constant when disturbing factors such has mutation and others are removed.
p² + pq + q² = 1 and p + q = 1
where p² is the frequency of the homozygous dominant genotype (RR) and q² is the frequency of the homozygous recessive genotype (rr) and 2pq is the frequency of heterozygous genotype (Rr). p represent the frequency of "R" and q represent "g". since the coefficient against the green/green homozygote is 0.30 then
the fitness of the green/green homozygote = 1 - 0.3 = 0.7
Chromosomes condense during prophase
I think the correct answer from the choices listed above is the first option. The circumstances that this condition would manifest would be if the child is a male and its mother has the recessive allele. X-linked recessive inheritance<span> is a mode of </span>inheritance<span> in which a </span>mutation<span> in a </span>gene<span> on the </span>X chromosome<span> causes the phenotype to be expressed in males </span><span>and in females who are homozygous for the gene mutation</span>
