Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
Answer:
A sister chromatid refers to the identical copies (chromatids) formed by DNA replication of a chromosome, with both copies joined by a common centromere.
Explanation:
Homologous chromosomes may or may not be the same as each other because they are derived from different parents.
Answer:
To understand the physical change and chemical change, one needs to know what is physical properties and what is the chemical properties of a substance.
Physical property is characteristic or trait of a substance that can be observed without converting the substance to a new substance. If there is any type of change in these physical properties like changing the appearance or form of matter and does not make a new substance, takes place it is called physical change.
A chemical change is a change in the matter of a substance that creates one or more new substances. This type of change includes the formation, color, of a precipitate, change in texture, and many other changes.
Answer:
Intially the glucose concentration is levelled and then the liquid level in side A will rise.
Explanation:
- Initially the liquid ob both sides are in isotonic condition.
- The membrane is permeable to glucose so glucose will diffuse from higher concentration (2 M) to lower concentration (1 M) until the concentration become equal (1.5 M) on both sides.
- Know, the Side A have 2 M sucrose and 1.5 M glucose and side B have 1 M glucose and 1 M sucrose.
- The side A will become hypertonic and side B will become hypotonic and water will start moving from side B to side A.
