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Ulleksa [173]
4 years ago
12

Are all quadratics factorable?

Mathematics
2 answers:
solmaris [256]4 years ago
8 0

Answer:

t really depends on whether you want to have complex factors or not. If you can have complex factors, every expression can be. If not, then only if b2≥4ac would they be factorable.

Take x2+1, it can be factored into (x−i)(x+i) but none of the factors are real.

Dima020 [189]4 years ago
6 0

Answer:

not all are but most of them are. if you are having a hard time use the quadratic equasion.

Step-by-step explanation:

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The landing restuarant order 200 flowers for mother day.the orderd carnation at 1.50$,Rose's at 5.75$and the daisies at 2.60$ ea
Vanyuwa [196]

Answer:

She ordered 80 carnations, 50 roses, and 70 daisies.

Step-by-step explanation:

Let x = number of carnations, y = number of roses, and z = number of daisies.  This problem gives us three equations.

 

First, remember that we multiply the price of each flower by the number bought then add up the subtotals, that gives the total amount paid.

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1.50x + 5.75(z - 20) + 2.60z = 589.50

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x + 2z - 20 = 200

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If you solve the rewrite second equation for x, you get x = 220 - 2z.  Therefore, you can substitute 220 - 2z in for x in the rewritten first equation, and then solve for z.

 

1.50 (220 - 2z) + 8.35z = 704.50

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If you have z = 70, then x = 220 - 2(70) = 80 and y = 70 - 20 = 50.

 

She ordered 80 carnations, 50 roses, and 70 daisies.

*HOPE THIS HELPED!!! :D)

4 0
4 years ago
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Answer:

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