Option D:
ΔCAN ≅ ΔWNA by SAS congruence rule.
Solution:
Given data:
m∠CNA = m∠WAN and CN = WA
To prove that ΔCAN ≅ ΔWNA:
In ΔCAN and ΔWNA,
CN = WA (given side)
∠CNA = ∠WAN (given angle)
NA = NA (reflexive side)
Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.
Hence option D is the correct answer.
Answer:
x = - 33
Step-by-step explanation:
Given
(x + 6) = - 18
Multiply both sides by 3 to clear the fraction
2(x + 6) = - 54 ( divide both sides by 2 )
x + 6 = - 27 ( subtract 6 from both sides )
x = - 33
Answer: positive: 1; negative: -1, -2, -3
Step-by-step explanation: 1 is greater than -2 and less than 2
-1, -2, and -3 are all greater than it equal to -3 and less than 2
The answer is of the figure is 24
Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD =
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
=
=
= 0.6