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antoniya [11.8K]
3 years ago
5

Help me please! 30 points!

Mathematics
2 answers:
pshichka [43]3 years ago
7 0

Answer: The answer is C :) hope that helps

Step-by-step explanation:

LuckyWell [14K]3 years ago
5 0

Answer: Range is  $104.00

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HELLPPPP NEED ThIS DONE IN ! MIn WHATS 1+1<br> a.4<br> b.1<br> C.6<br> D.3
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6 0
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How do you simplify (-5x^5+14)-(11x^2+1+11x^5)
lord [1]
(-5x ⁵+14)-(11x ²+1+11x ⁵)
Like terms: -5x ⁵-11x ⁵ = -16x ⁵
Like terms also: 14-1 = 13
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6 0
3 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
The mean length of 7 planks of wood is 1.35m. When an extra plank of wood is added, the mean length of a plank of wood increase
azamat

Answer: Hello There!................

Mean = Sum of observation / total number of observation

Mean = 1.35m

1.35  = Sum of length of 7 wood planks/ 7

1.35*7 = Sum of the length of 7 wood planks

9.45 = Sum of the length of 7 wood planks

Let the length of extra added wood plank = x

So,

(Sum of the length of 7 wood planks + x) / 8 = 1.4m

(9.45 + x) / 8 = 1.4

9.45 + x = 1.4 * 8

9.45 + x = 11.2

x = 11.2- 9.45

= 1.75

So,

The length of extra added wood plank = 1.75m

Step-by-step explanation:

Mark me brainest please. Hope this helps. Anna ♥

6 0
2 years ago
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