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ANTONII [103]
3 years ago
11

Can an opposite and an absolute value of an integer be the same?

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Yes and opposite and an absolute value of an integer will be the same.

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Solve the equation <br> 2 x 1 1/2 = 46
Leokris [45]

Answer:

the Question is inappropriate

GOOD LUCK FOR THE FUTURE! :)

7 0
3 years ago
Write 7/3,41/9,9/5 in simplest form
Soloha48 [4]

Answer:

  • \frac{7}{3} = 2 1/3 ← Mixed Fraction
  • \frac{41}{9} = 4 5/9
  • \frac{9}{5} = 1 4/5

* Hopefully this helps:) Mark me the brainliest:)

8 0
3 years ago
Read 2 more answers
A square garden has an area of 400 square feet. Each side of the garden is (x-10) feet in length.
Mandarinka [93]

Answer:

400 = (x - 10)²

x² -20x -300 = 0

x = 30 and x = -10

Length side of the garden = 20 feet

Step-by-step explanation:

Given:

Area of square garden = 400 square feet

Length side of the garden = (x - 10) feet

Find:

Length side of the garden

Computation:

Area of square = side²

Area of square garden = Length side of the garden²

400 = (x - 10)²

400 = x² -20x + 100

x² -20x -300 = 0

x² -30x  + 10x -300 = 0

x(x - 30) + 10(x - 30) = 0

(x - 30)(x + 10) = 0

So,

x = 30 and x = -10

Use x = 30 positive number

Length side of the garden = (x - 10) feet

Length side of the garden = (30 - 10) feet

Length side of the garden = 20 feet

7 0
3 years ago
If h(x) = 6 - X, what is the value of (h*h)(10)?
Vikentia [17]

The value of \bold{ h(h(10))=10}

<u>Solution:</u>

Given: h(x) = 6 - x

To find: The value of (h*h)(10)

We know that, (h*h)(x)=h(h(x))

which is,

\Rightarrow h(h(x))=6-(6-x)=x

On solving we get,

\Rightarrow6-6+x=x

So, for x = 10 it will be,

h(h(10))=10

Hence, the required value is 10.

5 0
3 years ago
Does this table represent a function or not? Why or why not?
Basile [38]

Answer:

No

Step-by-step explanation:

For something to be a function, there must be no duplicate x values, or if there is they must represent the same y. The table has a duplicate value of 2 so it is not a function.

I hope this helps!

3 0
3 years ago
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