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3 years ago

Solve the equation and enter the value of x below. X + +(-8) = 2 X =

Mathematics

1 answer:

hichkok12 [17]3 years ago

7 0

Answer:

x = 10.

Step-by-step explanation:

x + (-8) = 2.

First, isolate x by adding 8 to both sides.

x = 8 + 2.

Next, solve.

x = 10.

Finally, you can come to the conclusion that x = 10. Always plug in your answer to make sure it works.

10 - 8 = 2.

2 = 2.

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Suri's age is 4 less than 3 times her cousin's age. Suri is 17 years old. Which method can be used to find c, her cousin's age?

Mila [183]

Answer:

7 years

Step-by-step explanation:

Suri's age=17 years

Her cousin's age =c

Suri's age is 4 less than 3 times her cousin's age

4 less than 3 times her cousin's age means subtract 4 from 3 times her cousin's age

17=3c - 4

Find c which is her cousin's age

Add 4 to both sides

17+4=3c - 4 + 4

17+4=3c

21=3c

Divide both sides by 3

21/3=3c/3

7=c

Therefore,

C= 7

Her cousin's age = 7 years

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3 years ago

The total pay for 12 hours of work at a base rate of (p) per hour plus a temporary raise of $2.50 per hour. How would I write th

Naddika [18.5K]

12P+2.50 HOPE THIS HELPS

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3 years ago

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uranmaximum [27]

Step-by-step explanation:

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10 gallons of gas = $29.50

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7 0

3 years ago

PLEASE HELP I NEED TO PASS MATH!

fgiga [73]

Answer:

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Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

A, B and C are events such that P(A) = 1/3, P(B) = ¼, and P(C) = 1/5. Find P(AUBUC) under each of the following assumptions: a)

marta [7]

(a) If $A,B,C$ are mutually exclusive, then

$P(A\cap B)=P(A\cap C)=P(B\cap C)=P(A\cap B\cap C)=0$

so we have

$P(A\cup B\cup C)=P(A)+P(B)+P(C)=\dfrac{47}{60}$

(b) If $A,B,C$ are mutually independent, then

$P(A\cap B)=P(A)P(B),$

$P(A\cap C)=P(A)P(C),$

$P(B\cap C)=P(B)P(C),$

$P(A\cap B\cap C)=P(A)P(B)P(C)$

so that

$P(A\cup B\cup C)=P(A)+P(B)+P(C)-(P(A\cap B)+P(A\cap B)+P(B\cap C))+P(A\cap B\cap C)$

$P(A\cup B\cup C)=\dfrac{47}{60}-\left(\dfrac1{12}+\dfrac1{15}+\dfrac1{20}\right)+\dfrac1{60}$

$P(A\cup B\cup C)=\dfrac35$

5 0

3 years ago