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vichka [17]
2 years ago
11

How to write a decimal as a fraction?

Mathematics
1 answer:
love history [14]2 years ago
5 0

Answer:

Step-by-step explanation:

Convert Decimals to Fractions

Step 1: Write down the decimal divided by 1, like this: decimal 1.

Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.)

Step 3: Simplify (or reduce) the fraction.

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Create a Sample Space diagram and work out the probability - There is a 4 sided dice (numbers 1 to 4) and an 8 sided dice (numbe
tester [92]

Answer:

7 / 16

Step-by-step explanation:

Sample space is attached below :

Theoretical Probability of any event A

P(A) = (number of required outcome / Total number of possible outcomes)

Required outcome = sum greater than 7 = 14

Total number of possible outcomes = 32

P(sum greater than 7) = 14 / 32

P(sum greater than 7) = 7 / 16

3 0
2 years ago
The size of a television screen is given as 95 cm, correct to the nearest 5 cm.
timofeeve [1]

Answer:

U B = 100.5

Step-by-step explanation:

the upper bound of the size of the television screen= 95.5 since it is corrected to the nearest 5 then the U B =100.5 cm

7 0
2 years ago
I need it ASAP, Questions are attached as a photo
ELEN [110]

Answer:

8- 26 cm

7- 85 cm^2

1-23 cm

5 0
2 years ago
Let e1= 1 0 and e2= 0 1 ​, y1= 4 5 ​, and y2= −2 7 ​, and let​ T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps
Furkat [3]

Answer:

The image of \left[\begin{array}{c}4&-4\end{array}\right] through T is \left[\begin{array}{c}24&-8\end{array}\right]

Step-by-step explanation:

We know that T: IR^{2}  → IR^{2} is a linear transformation that maps e_{1} into y_{1} ⇒

T(e_{1})=y_{1}

And also maps e_{2} into y_{2}  ⇒

T(e_{2})=y_{2}

We need to find the image of the vector \left[\begin{array}{c}4&-4\end{array}\right]

We know that exists a matrix A from IR^{2x2} (because of how T was defined) such that :

T(x)=Ax for all x ∈ IR^{2}

We can find the matrix A by applying T to a base of the domain (IR^{2}).

Notice that we have that data :

B_{IR^{2}}= {e_{1},e_{2}}

Being B_{IR^{2}} the cannonic base of IR^{2}

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

T(\left[\begin{array}{c}1&0\end{array}\right])=\left[\begin{array}{c}4&5\end{array}\right]   (Data of the problem)

T(\left[\begin{array}{c}0&1\end{array}\right])=\left[\begin{array}{c}-2&7\end{array}\right]   (Data of the problem)

Writing the matrix A :

A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]

Now with the matrix A we can find the image of \left[\begin{array}{c}4&-4\\\end{array}\right] such as :

T(x)=Ax ⇒

T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]

We found out that the image of \left[\begin{array}{c}4&-4\end{array}\right] through T is the vector \left[\begin{array}{c}24&-8\end{array}\right]

3 0
2 years ago
Find the exact value of c
Rainbow [258]

Answer:

depends on the question

8 0
2 years ago
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