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Inessa [10]
3 years ago
13

Susan shakes a bottle of oil and vinegar salad dressing, then sets it on the table. After a while, the oil rises to the top and

the vinegar settles on the bottom of the bottle. Why does this happen?
Chemistry
1 answer:
MrMuchimi3 years ago
8 0
That happens because in oil and vinegar have a certain density weight.
-A<span>n object will float if it is less dense than the liquid it is placed in.
<span>-An object will sink if it is more dense than the liquid it is placed in.</span></span>
You might be interested in
You make two dilutions. You take 83.52 mL of the stock solution and dilute to 500.0 mL to make Solution #1. You then add 52.27 m
kati45 [8]

Answer:

The answer to the question is;

The concentration of the Solution #1 in terms of molarity is

0.16704X moles/litre.

Explanation:

Let the concentration of the stock solution be X moles/liter

Therefore, 83.52 ml of the stock solution contains

83.52×(X/1000) moles

Dilution of 83.52 ml of X to 500 ml gives solution 1 with a concentration of

500 ml of solution 1 contains 83.52×(X/1000) moles

Therefore 1000 ml or 1 litre contains 2×83.52×(X/1000) moles = 0.16704X moles/litre

The molarity of solution 1 is 0.16704X moles/litre.

8 0
4 years ago
At 46°C a sample of ammonia gas exerts a pressure of 5.3 atm. What is the pressure when the volume of the gas is reduced to one-
snow_lady [41]

Hello there!

As you may know, pressure and volume have an inverse relationship. This means that as pressure increases, volume decreases (and as volume increases, pressure decreases).

In this problem, the volume of the gas is reduced to 0.250 its original value. This means that the pressure should be higher than it was originally.

We can use Boyle's Law to solve this problem, seeing that temperature is kept constant.

P1V1 = P2V2

Let's rearrange this equation to isolate the variable we need, P2.

P1V1

-------   = P2

 V2

That's better! Now that we have that down, let's plug in the numbers we were given.

(5.3atm) * (V1)

-------------------- = P2

0.25(V1)

We can get rid of V1, as the number would be equal to 1 (anything divided by itself is equal to 1).

5.3atm

---------- = 21.2 atm

0.25L

Now, while the number is significantly higher, this is quite reasonable.

Let's plug it in and see if we get what we should:

5.3(V1) = (0.25V1)(21.2)

--------

0.25V1

21.2 atm = 21.2 atm

Seems right to me!

Feel free to comment if you need any more help. :)

5 0
3 years ago
What is the molality of a solution of water and kcl if the freezing point of the solution is –3mc030-1.jpgc?
Natasha_Volkova [10]
We will use the expression for freezing point depression ∆Tf
     ∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is 
     ∆Tf = 0C - (-3°C) = 3°C 
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and  one Cl- ion:
     KCl → K+ + Cl- 
Therefore, the molality m of the solution can be calculated as 
     3 = 2 * 1.86 * m
     m = 3 / (2 * 1.86)
     m = 0.80 molal
4 0
3 years ago
7. State the relationship between the concentration of ions and the boiling point for these solutions.
balu736 [363]

Answer:

  • 7. Linear relationship.

  • 8. Because ions carry charge that can move freely in solution.

  • 9. Solute: NaCl

            Solvent: H₂O

Explanation:

7. Elevation of the boling point.

The elevation of the boiling point of a solution respect to the pure solvent is a colligative property, meaning that it is proportional to the concentration of the solute particles.

        \Delta T_b=K_b\times i\times C

        T_b=T_b^0+K_b\times i\times C

Where, ΔTb is the elevation on the boiling point, Tb is the (elevated) boiling of the solution, point, Tb° is the boiling point of the pure solvent, i is the Van't Hoof factor, and C is the molal concentration (molality)

Thus the relation of the boiling point with the mola concentration (molality) is linear.

Using the table and some calculations, you can determine this relationship:

Trial  Mass of water   mass NaCl    moles NaCl     m             Tb

             kg                      g                   mol            mol/kg       ºC

  1        0.1                     8.76              0.15               1.5             101.5

 2        0.1                    17.52             0.30              3.0             103.1

 3        0.1                    20.28            0.45              4.5             104.6

 4        0.1                   35.04             0.60              6.0             106.1        

The number of moles for each trial were determinated dividing the mass in grams of the solute by the molar mass (58.44g/mol).

The molality concentrations (mole of solue per kg of solvent) were determined dividing the number of moles of each trial by the amount of solvent in kg.

As you see in the table, the column of Tb increases by an approximate constant value of 1.5ºC and the column of the molal concentration increases at a constant value of 0.15mol. Thus there is a constante rate of change of 1.5ºC/0.15mol = 10ºC/mol.

Since a constant rate of change means constant slope, this you conclude that the relationship is linear.

8. Ability to conduct an electric current.

Electric current is the flow of charges.

Ions are charged particles. There are positive ions (cations) and negative ions (ions) dissolved; this is, they are free to move in solution.

Current is the rate of flow of the charge, thus the greater the number of ions in solution, the greater the flow of charge, which is a greater current.

That explains why the greater the concentration of the ions in the solution the greater the abiity fo the solution to conduct electricity.

Pure water has a low concentration of ions (H⁺ and OH⁻) thus it has a very low ability to conduct electricity. But adding a solute, like an acid, a base, or a salt (like NaCl in this case), increases the number of ions in solution, and thus a solution with a high concetration of solute will have a great ability to conduct electricity.

9. Identify the solute and solvent.

  • The<em> solute </em>is the component of a solutions that is present in relatively small quantities and is dissolved. In this case the solute is the salt, sodium chloride, NaCl.

  • The <em>solvent</em> is the component of the solution that is present in greater amount and is able to dissolve the solute. In this case the solvent is water, H₂O.

The concentrations of the solute normally are relatively low, because they are the component with less particles in the solution.

5 0
3 years ago
H2SO4 is added to a large beaker of water. How is the solution different from the original water?
asambeis [7]
When concentrated sulfuric acid, H2SO4(l), is added to water it will form a solution containing hydrogen ions and hydrogen sulfate ions. H2SO4 is a strong acid, but only for the first H+. The remaining HSO4^- is a weak acid. Since it forms an acidic solution, it will change blue litmus to red.
4 0
4 years ago
Read 2 more answers
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