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topjm [15]
3 years ago
12

H2SO4 is added to a large beaker of water. How is the solution different from the original water?

Chemistry
2 answers:
asambeis [7]3 years ago
4 0
When concentrated sulfuric acid, H2SO4(l), is added to water it will form a solution containing hydrogen ions and hydrogen sulfate ions. H2SO4 is a strong acid, but only for the first H+. The remaining HSO4^- is a weak acid. Since it forms an acidic solution, it will change blue litmus to red.
Rus_ich [418]3 years ago
4 0

Answer:

The new solution is a homogeneous mixture and will have a lower pH i.e. more acidic.

Explanation:

The solution is different is different in 2 ways:

1) The original water is a pure solution. Water is a polar solvent and so is H2SO4. When the later is added to water it is completely dispersed and results in a solution which is essentially a homogenous mixture of two liquids.

2) Secondly the pH of water is neutral i.e.7. Sulfuric acid (H2SO4) is a strong acid which dissociates completely to release H+ ions in solution. This increases the concentration of H+ ions. Since pH = -log[H+], the pH will decrease making the solution more acidic.

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What mass of iron is needed to react with sulfur in order to produce 96 grams of
fiasKO [112]

Answer:

51.69 g of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Fe + 3S —> Fe₂S₃

Next, we shall determine the mass of Fe that reacted and the mass of Fe₂S₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 2 × 56 = 112 g

Molar mass of Fe₂S₃ = (2×56) + (3×32)

= 112 + 96

= 208 g/mol

Mass of Fe₂S₃ from the balanced equation = 1 × 208 = 208 g

SUMMARY:

From the balanced equation above,

112 g of Fe reacted to produce 208 g of Fe₂S₃.

Finally, we shall determine the mass of Fe needed to produce 96 g of Fe₂S₃. This can be obtained as follow:

From the balanced equation above,

112 g of Fe reacted to produce 208 g of Fe₂S₃.

Therefore, Xg of Fe will react to produce 96 g of Fe₂S₃ i.e

Xg of Fe = (112 × 96)/208

Xg of Fe = 51.69 g

Thus, 51.69 g of Fe is needed for the reaction.

8 0
3 years ago
At 700 K, the reaction 2SO2(g) + O2(g) <====> 2SO3(g) has the equilibrium constant Kc = 4.3 x 106. At a certain instant, f
nadya68 [22]

Answer:

The system is not in equilibrium and will evolve left to right to reach equilibrium.

Explanation:

The reaction quotient Qc is defined for a generic reaction:

aA + bB → cC + dD

Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where the concentrations are not those of equilibrium, but other given concentrations

Chemical Equilibrium is the state in which the direct and indirect reaction have the same speed and is represented by a constant Kc, which for a generic reaction as shown above, is defined:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where the concentrations are those of equilibrium.

This constant is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

Comparing Qc with Kc allows to find out the status and evolution of the system:

  • If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.
  • If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.
  • If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

In this case:

Q=\frac{[So_{3}] ^{2} }{[SO_{2} ]^{2}* [O_{2}] }

Q=\frac{10^{2} }{0.10^{2} *0.10}

Q=100,000

100,000 < 4,300,000 (4.3*10⁶)

Q < Kc

<u><em> The system is not in equilibrium and will evolve left to right to reach equilibrium.</em></u>

3 0
2 years ago
Is it always easy to classify research as applied or pure? Explain.
Luda [366]

No..since research can take different format

3 0
2 years ago
Activation energy is (blank)
timurjin [86]

B. The energy barrier between reactants and products

hope this helps!

(:

7 0
2 years ago
Read 2 more answers
An aluminum can (Al) has a mass of 15.8 grams. How many atoms of aluminum are in the can?
Naddik [55]

Answer:

i think this is the answer you can try it tho...

Explanation:

Notice that the value 12.01 grams of natural carbon is the same as the atomic mass value (12.01 amu). It also tells us that 26.98 grams of aluminum contains exactly 6.022 x 1023 atoms of aluminum.

5 0
2 years ago
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