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topjm [15]
3 years ago
12

H2SO4 is added to a large beaker of water. How is the solution different from the original water?

Chemistry
2 answers:
asambeis [7]3 years ago
4 0
When concentrated sulfuric acid, H2SO4(l), is added to water it will form a solution containing hydrogen ions and hydrogen sulfate ions. H2SO4 is a strong acid, but only for the first H+. The remaining HSO4^- is a weak acid. Since it forms an acidic solution, it will change blue litmus to red.
Rus_ich [418]3 years ago
4 0

Answer:

The new solution is a homogeneous mixture and will have a lower pH i.e. more acidic.

Explanation:

The solution is different is different in 2 ways:

1) The original water is a pure solution. Water is a polar solvent and so is H2SO4. When the later is added to water it is completely dispersed and results in a solution which is essentially a homogenous mixture of two liquids.

2) Secondly the pH of water is neutral i.e.7. Sulfuric acid (H2SO4) is a strong acid which dissociates completely to release H+ ions in solution. This increases the concentration of H+ ions. Since pH = -log[H+], the pH will decrease making the solution more acidic.

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3 years ago
Photosynthesis can be represented by6CO2(g)+6H2O(l)⇌C6H12O6(s)+6O2(g)Which of the following will be false when the photosynthesi
denis-greek [22]

Answer:

The concentration of O2 will begin decreasing and The concentrations of CO2 and O2 will be equal.

Explanation:

Equilibrium occurs when the velocity of the formation of the products it's equal to the velocity of the formation of the reactants, thus the concentrations of the compounds remain constant.

Analyzing the information and the reaction given, we can notice that in equilibrium the rate (velocity) of formation of O2 (product) is equal to the rate of formation of CO2 (reactant).

As the CO2 and H2O are placed in the reaction, the Le Chateliêr's principle states that the equilibrium must shift to reestablish the equilibrium, thus, they must be consumed, and the concentration of O2 must increase.

As state above, in equilibrium, the concentrations didn't change, thus, the concentrations of CO2 and O2 will not change.

The concentrations of CO2 and O2 depends on the rate of the reaction and the initial quantities presented, so it's not possible to affirm they'll be equal.

8 0
3 years ago
Identify the group of elements that does not readily combine with other elements.
7nadin3 [17]
Noble gases
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4 0
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Answer:

C4H90H

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6 0
3 years ago
What is the volume of 0.80 grams of O2 gas at STP? (5 points) Group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l
Anarel [89]

Answer:

0.56 liters

Explanation:

First we <u>convert 0.80 grams of O₂ into moles</u>, using its molar mass:

  • 0.80 g ÷ 32 g/mol = 0.025 mol

At STP, 1 mol of any given mass occupies 22.4 L. With that information in mind we <u>calculate the volume that 0.025 moles of O₂ gas would occupy</u>:

  • 0.025 mol * 22.4 L/mol = 0.56 L

Thus the answer is 0.56 liters.

3 0
2 years ago
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