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zalisa [80]
3 years ago
13

A rectangular field measures 6.0 m by 8.0 m. What is the area of the field in square centimeters (cm2)? Use the formula: Area =

length × width.
Chemistry
2 answers:
zhenek [66]3 years ago
7 0
The correct answer is 4800 cm^2

Step By Step Answer:
Length times width:
6.0 * 8.0 = 48
Translate m to cm:
4800 cm^2

Help this helps!
lidiya [134]3 years ago
4 0

Answer : The area of the field is, 480000cm^2

Explanation : Given,

Length of rectangular field = 8.0 m = 800 cm

Width of rectangular field = 6.0 m = 600 cm

Conversion used : (1 m = 100 cm)

Formula used :

Area = Length × Width

Now put all the given values in this formula, we get the area of the field.

Area = 800 cm × 600 cm

Area = 480000m^2

Therefore the area of the field is, 480000cm^2

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I think the correct answer from the choices listed above is option A. When you drink <span>milk of magnesia for an upset stomach, most likely, it would raise the pH in your body since it reacts with the acid inside reducing the amount of acid. Hope this answers the question.</span>
8 0
3 years ago
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if you help me ill give you more brainly's. plzz help.At 1 atm, how much energy is required to heat 37.0 g of H2O(s) at –10.0 °C
artcher [175]

Answer:

116.3 kJ

Step-by-step explanation:

Three heat transfers are involved

q = Heat to warm ice + heat to melt ice + heat to warm water + heat to evaporate water + heat to warm steam

q =      q₁      +     q₂        +     q₃       +     q₄          +     q₅

q = mC₁ΔT₁ + mΔH_fus + mC₃ΔT₃ + mΔH_vap + mC₅ΔT₅

<em>Step 1</em>: Calculate q₁

m = 37.0 g

C₁ = 2.010 J·°C⁻¹g⁻¹

ΔT₁ = T_f – T_i  

ΔT₁ = 0.0 – (-10.0)

ΔT₁ = 10.0 °C  

q₁ = 37.0 × 2.010 × 10.0  

q₁= 743.7 J

q₁= 0.7437 kJ

===============

<em>Step 2</em>. Calculate q₂

ΔH_fus = 334 J/g

q₂ = 37.0 × 334

q₂ = 12 360 J

q₂ = 12.36 kJ

===============

Step 3: Calculate q₃

C₃ = 4.179 J·°C⁻¹g⁻¹

ΔT₃ = T_f – T_i  

ΔT₃ = 100 – 0  

ΔT₃ = 100 °C

q₃ = 37.0 × 4.179 × 100  

q₃ = 15 460 J

q₃ = 15.46 kJ

===============

<em>Step 4</em>. Calculate q₄

ΔH_vap = 2260 J/g

q₄ = 37.0 × 2260

q₄ = 83 620 J

q₄ = 83.62 kJ

===============

<em>Step 5</em>. Calculate q₅

C¬₅ = 2.010 J·°C⁻¹g⁻¹

ΔT₅ = T_f – T_i  

ΔT₅ = 155.0 – 1000  

ΔT₅ = 55.0 °C

q₅ = 37.0 × 2.010 × 55

q₅ = 4090 J

q₅ = 4.090 kJ

===============

Step 6. Calculate q

q = 0.7437 + 12.36 + 15.46 + 83.62 + 4.090

q = 116.3 kJ

The heat required is 116.3 kJ.

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3 years ago
Answer the following questions:
Burka [1]

Answer:

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Explanation:

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Heat energy is transferred by conduction whenever molecules?
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I think the answer is D

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Oil and water.

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