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Y_Kistochka [10]
3 years ago
11

How would you solve the area

Mathematics
1 answer:
zvonat [6]3 years ago
8 0
Check the picture below.

so the composite is just 2 triangles, one rectangle and one parallelogram.

we know the height and base of the triangles and length and width of the rectangle.

now, the parallelogram, we can simply split in in two triangles and a rectangle, like you see the split in the middle, and that gives us two more triangles and one rectangle.

so, we can simply get the area of each of those figures and sum them up, and that's the area of the composite.

\bf \stackrel{\textit{left triangle}}{\cfrac{1}{2}(11)(8)}~~+~~\stackrel{\textit{left rectangle}}{11\cdot 9}~~+~~\stackrel{\textit{upper middle triangle}}{\cfrac{1}{2}(11)(2)}
\\\\\\
+~~\stackrel{\textit{middle rectangle}}{7\cdot 11}~~+~~\stackrel{\textit{lower middle triangle}}{\cfrac{1}{2}(11)(2)}~~+~~\stackrel{\textit{right triangle}}{\cfrac{1}{2}(8)(9)}\\\\
-------------------------------\\\\
44+99+11+77+11+36\implies 278

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Answer:

67 and 69

Step-by-step explanation:

8 0
3 years ago
Majesty Video Production Inc. wants the mean length of its advertisements to be 26 seconds. Assume the distribution of ad length
Paladinen [302]

Answer:

a) By the Central Limit Theorem, approximately normally distributed, with mean 26 and standard error 0.44.

b) s = 0.44

c) 0.84% of the sample means will be greater than 27.05 seconds

d) 98.46% of the sample means will be greater than 25.05 seconds

e) 97.62% of the sample means will be greater than 25.05 but less than 27.05 seconds

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation(also called standard error) s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 26, \sigma = 2, n = 21, s = \frac{2}{\sqrt{21}} = 0.44

a. What can we say about the shape of the distribution of the sample mean time?

By the Central Limit Theorem, approximately normally distributed, with mean 26 and standard error 0.44.

b. What is the standard error of the mean time? (Round your answer to 2 decimal places)

s = \frac{2}{\sqrt{21}} = 0.44

c. What percent of the sample means will be greater than 27.05 seconds?

This is 1 subtracted by the pvalue of Z when X = 27.05. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{27.05 - 26}{0.44}

Z = 2.39

Z = 2.39 has a pvalue of 0.9916

1 - 0.9916 = 0.0084

0.84% of the sample means will be greater than 27.05 seconds

d. What percent of the sample means will be greater than 25.05 seconds?

This is 1 subtracted by the pvalue of Z when X = 25.05. So

Z = \frac{X - \mu}{s}

Z = \frac{25.05 - 26}{0.44}

Z = -2.16

Z = -2.16 has a pvalue of 0.0154

1 - 0.0154 = 0.9846

98.46% of the sample means will be greater than 25.05 seconds

e. What percent of the sample means will be greater than 25.05 but less than 27.05 seconds?"

This is the pvalue of Z when X = 27.05 subtracted by the pvalue of Z when X = 25.05.

X = 27.05

Z = \frac{X - \mu}{s}

Z = \frac{27.05 - 26}{0.44}

Z = 2.39

Z = 2.39 has a pvalue of 0.9916

X = 25.05

Z = \frac{X - \mu}{s}

Z = \frac{25.05 - 26}{0.44}

Z = -2.16

Z = -2.16 has a pvalue of 0.0154

0.9916 - 0.0154 = 0.9762

97.62% of the sample means will be greater than 25.05 but less than 27.05 seconds

8 0
3 years ago
Can someone please help me find the answer to this question?
rodikova [14]

Answer:

first option is correct

have a nice day

4 0
1 year ago
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What is the answer for 6.8 6.9 6.10
Dafna1 [17]
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6 0
3 years ago
A bag contains 4 red marbles, 6 blue marbles and 7 green marbles. If three marbles are drawn out of the bag, what is the probabi
yawa3891 [41]

Answer:

Step-by-step explanation:

Total marble = 4+6+7 = 17

Number of green = 7

Prob(1st green) = 7/17

Now their are 6 green left and 16 marble

Prob(2nd green) = 6/16 = 3/8

Now their are 5 green left and 15 marble

Prob(3rd green) = 5/15 = 1/3

Prob(1st and 2nd and 3rd green) will be = 7/17 × 3/8 × 1/3

= 7/(17×8)

= 7/136

3 0
3 years ago
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