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Aloiza [94]
3 years ago
13

△POQ~△ROS. Identify the coordinates of S and the scale factor. HELP ASAP!!

Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

S(-7,0) , 2/7

Step-by-step explanation:

To get coordinates of P we can see that

14*(2/7)=4

Now, to get coordinates of S, we have this equation :

x*\frac{2}{7}=-2

Multiply by 7 each side :

2x=-14

x=-7

y=0

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A = (-123) + 77 + (-257) + 23 – 43
irga5000 [103]

Answer:

A=-323

Step-by-step explanation:

A = (-123)+77+(-257)+23-43

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A = -280-43

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Hope this helps

7 0
3 years ago
Sin(42) = cos(x) <br> Solve for x
mariarad [96]

Answer:

X = 48

Step-by-step explanation:

When you type sin(42) in your calculator it will give you something around 0.669.

If you try reverse sinus sin-1(0.669) it will give you 42.

Therefore you can say that:

Cos(x) = 0.669

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Cos-1 (sin(42))

3 0
3 years ago
What angle is complementary to 2 ?
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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%​
Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%​

  • Selling price = cost price - discount ⇒ discount case
  • Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = \frac{160}{90}=\frac{16}{9}

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = \frac{20}{100} × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by \frac{16}{9} to find x

∵ 0.8x = \frac{16}{9}

- Divide both sides by 0.8

∴ x = \frac{20}{9}

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is \frac{20}{9}

- Find 20% of \frac{20}{9}

∵ Profit = 20% × \frac{20}{9} = \frac{20}{100}.\frac{20}{9}=\frac{4}{9}

- Add \frac{4}{9} to cost price to find the selling price

∴ The selling price of an orange = \frac{20}{9} + \frac{4}{9}

∴ The selling price of an orange = \frac{24}{9}

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ \frac{24}{9}

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0
3 years ago
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