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satela [25.4K]
2 years ago
5

There are 3 triangles and 6 circles. What is the simplest ratio of circles to triangles?

Mathematics
1 answer:
Kisachek [45]2 years ago
4 0

Answer:

2:1

Step-by-step explanation:

3 triangles/6 circles

divided by 3

is 1 triangle/2 circles

or 2 circles to 1 triangle

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Which is grater to least 56.01 56.10 or 56.011
lapo4ka [179]
The answer would be 56.10
4 0
2 years ago
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Xft
salantis [7]

Answer:

640.0

Step-by-step explanation:

7 0
3 years ago
If f and t are both even functions, is the product ft even? If f and t are both odd functions, is ft odd? What if f is even and
Natali5045456 [20]

Answer:

(a) If f and t are both even functions, product ft is even.

(b) If f and t are both odd functions, product ft is even.

(c) If f is even and t is odd, product ft is odd.

Step-by-step explanation:

Even function: A function g(x) is called an even function if

g(-x)=g(x)

Odd function: A function g(x) is called an odd function if

g(-x)=-g(x)

(a)

Let f and t are both even functions, then

f(-x)=f(x)

t(-x)=t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=f(x)t(x)

ft(-x)=ft(x)

The function ft is even function.

(b)

Let f and t are both odd functions, then

f(-x)=-f(x)

t(-x)=-t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=[-f(x)][-t(x)]

ft(-x)=ft(x)

The function ft is even function.

(c)

Let f is even and t odd function, then

f(-x)=f(x)

t(-x)=-t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=[f(x)][-t(x)]

ft(-x)=-ft(x)

The function ft is odd function.

7 0
2 years ago
Does the following equation determine y to be a function of x? y square=x+3
Phantasy [73]

Answer:

∴ y² = x + 3 is not a function

Step-by-step explanation:

* Lets explain how to solve the problem

- The definition of the function is every input (x) has only one

  output (y)

- Ex:

# y = x + 1 where x ∈ R , is a function because every x has only

  one value of y

# y² = x where x ∈ R , is not a function because y = ±√x, then one

  x has two values of y

* Lets solve the problem

∵ y² = x + 3

- Find y by taking √ for both sides

∴ y = ± √(x + 3)

- That means y = √(x + 3)  and y = - √(x + 3)

∵ (x + 3) must be greater than or equal zero because there is no

  square root for negative number

∴ x + 3 ≥ 0 ⇒ subtract 3 from both sides

∴ x ≥ -3

∴ x must be any number greater than or equal -3

- Let x = 0

∴ y = √(0 + 3) = √3 and y = - √(0 + 3) = -√3

∴ x = 0 has two values of y ⇒ y = √3 and y = -√3

- Any value of x greater than or equal 3 will have two values of y

∴ y² = x + 3 is not a function

5 0
3 years ago
What's your favorite subject?
nexus9112 [7]

Answer:

math thank you very much

6 0
3 years ago
Read 2 more answers
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