For a logarithmic function, we have a restriction on the domain.
Since log(0) isn't defined, we say that there is an asymptote at x = 0.
Thus, for the regular logarithmic function y = log(x), x > 0.
We can then say (x + 4) > 0, since that's when the function of a logarithm is defined as.
x + 4 > 0
x > -4
Thus, the domain of the logarithmic function is x > -4, where x is a real integer.
Hi, Soldier23!
6/2(1+2)
6/2(3)
6/2=3
3*3=9
I hope this helps;)
No, 3,0 the x is to the right three and the y is zero. But 0,3 the x is zero and the y is up three
