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Liula [17]
3 years ago
12

Determine whether the given value is a solution of the equation: x + 15 = 10; x=5 *

Mathematics
2 answers:
kobusy [5.1K]3 years ago
5 0

Answer:

It is not correct, x = -5

Step-by-step explanation:

disa [49]3 years ago
4 0

Answer:

no

Step-by-step explanation:

because 5+15=10

-15=15

x= -5

which means its NOT a solution because it equals -5

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Write the fraction or mixed number as a decimal. Use bar notation if the decimal is a repeating decimal: 4 1/2
enyata [817]

4.5 because 1/2 equals .5 and 4 equals for

4 0
3 years ago
Give the excluded values for the rational equation.<br><br> (3x)/(x-4)-(x+3)/(x+4)=(2x+7)/(x^(2)-16)
scoray [572]

\frac{3x}{x-4}  - \frac{x+3}{x-4} = \frac{2x+7}{x^2-16}

We factor the denominators

Factor x^2 - 16

x^2 - 4^2

We use a^2 - b^2 = (a+b)(a-b)

so x^2 - 4^2 = (x+4)(x-4)

Replace it in the given equation

\frac{3x}{x-4}  - \frac{x+3}{x-4} = \frac{2x+7}{(x+4)(x-4)}

Excluded values are the values that makes the denominator 0

we have (x-4)  and (x+4) in the denominator

We set the denominator =0 and solve for x

x-4 =0

Add 4 on both sides

x= 4

x+4=0

subtract 4 onboth side

so x= -4

Excluded values are x=-4 and x=4




8 0
3 years ago
Read 2 more answers
Given two functions f(x)=2x+4 and g(x)=−1/5x−3 , what is the function rule for (f+g)(x) ?
Angelina_Jolie [31]

The definition is pretty simple:

(f+g)(x) = f(x)+g(x)

So, we only have to sum the expressions:

f(x)+g(x) = 2x+4 - \dfrac{1}{5}x-3 = \dfrac{9}{5}x+1

5 0
3 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

  • |C| = \sqrt{a^2+b^2}

Then, the work consists in finding pairs (a,b) for which:

  • \sqrt{a^2+b^2}=3

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

I will use b =0.5, b = 1, b = 1.5, b = 2

b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i
4 0
3 years ago
A ratio is defined as
Harrizon [31]
A ratio is a one or more letter term
5 0
3 years ago
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