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Darya [45]
3 years ago
12

If a piece of ribbon is 6 and 1 over 4. feet long, how long is it in inches?

Mathematics
1 answer:
timama [110]3 years ago
5 0
The piece of ribbon would be 75 inches. The ribbon would be 75 inches because 1 foot would be 12 inches and you would multiply 12 by 6 to get 72. Then, 1/4 of a foot would be 3 inches because you could divide 12 and 4(the denominator you are dealing with) to get 3. Then, add 72 + 3 to get 75. Hope this helps!
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2.\\ \\ z^2-z=0\\ \\z(x-1)=0\\ \\z=0 \ \ \ or \ \ \ z-1 =0 \ \ | +1\\ \\z-1+1 =0 +1 \\ \\x=0 \ \ \ or \ \ \ z=1


3.\\ \\m^2+13m+40=0 \\ \\a=1 ,\ b=13, \ c=40 \\ \\\Delta =b^2-4ac =13^2-4\cdot 1\cdot 40=169 - 1600=-1431 \\ \\and \ we \ know \ when \ \Delta \ is \ negative, \ theres \ no \solution


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5.\\ \\q^2+7q=0 \\ \\q(q+7)=0\\ \\q=0 \ \ \ or \ \ \ q+7 =0\ \ |-7\\ \\q+7-7=0-7\\ \\q=0 \ \ \ or \ \ \ q=-7


6.\\ \\k^2+2k=0\\ \\k(k+2)=0\\ \\k=0 \ \ \ or \ \ \ k+2 =0\ \ |-2\\ \\k+2-2=0-2\\ \\k=0 \ \ \ or \ \ \ k=-2


7. \\ \\ x^2-3x-70=0 \\ \\a=1,\ b=-3, \ c=-70 \\ \\\Delta =b^2-4ac = (-3)^2-4\cdot 1\cdot (-70)= 9+280=289\\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{3-\sqrt{289}}{2 }=\frac{ 3-17}{2}=\frac{-14}{2}=-7

x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{3+\sqrt{289}}{2 }=\frac{ 3+17}{2}=\frac{20}{2}=10\\ \\(x+7)(x-10)=0


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x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-7+\sqrt{289}}{2 }=\frac{ -7+17}{2}=\frac{ 10}{2}= 5\\ \\(x+12)(x-5)=0


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x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{225}}{2 }=\frac{ -9+15}{2}=\frac{6}{2}=3\\ \\(x+11)(x-3)=0


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7 0
3 years ago
Pls anwers the question pls it has pictures as well pls pls pls pls pls pls pls
azamat

Answer:

a = $80.3

b = $80

c = 4

d = 16

e = 4

f = 88

g = $132

h = 33%

i = 6

j = 30

k = 21

l = $90

m = $36

o = 21/50

p = 105

q = 7

r = 8 cm

s = 2.4

t = 4

u = 400cm

v = $280

Step-by-step Explanation:

==>Increasing $72 by 10% to get a

a = 110% of $72 = 110% × $73

a = 1.1 × 73

a = $80.3

==>a ($80.3) rounded to the nearest 10 to find b = $80

b = $80

==>Writing b (80) as the product of its primes I.e.

b = 2^{c} * 5

Thus, 80 = 2⁴ * 5

c = 4

==>Calculating c² = d

d = 4² = 16

d = 16

==> ²/8 of d = e

e = ²/8 × 16

e = 2 × 2

e = 4

==> e% of 2200 = f

f = 4% × 2200

f = 0.04 × 2200

f = 88

==>Converting £f to $ = g

If £1 = $1.5,

£88 = $g

1 × g = 1.5 × 88

g = $132

==> Converting \frac{g}{400} into % = h%

h = 132÷400 ×100

h = 0.33 × 100

h = 33%

==> √(h + 3) = i

i = √(33 + 3)

i = √36

i = 6

==> i × (3 + 2) = j

j = 6 × (3 + 2)

j = 6 × 5

j = 30

==> j% of 70 = k

k = j% × 70

k = 30% × 70

k = 0.3 × 70

k = 21

==> If k bottles = $63, 30 bottles = $l

21 bottles = $63

30 bottles = $l

21 × l = 63 × 30

21l = 1,890

l = 1,890/21

l = $90

==>If Tim and Mike (m) shares $90 in the ratio 3:2, Mike (m) would receive thus:

⅖ × $90 = m

m = 0.4 × 90

m = $36

==> √m + m = n

n = √36 + 36

n = 6 + 36

n = 42

==>Converting n% to fraction = o

Thus, o = 42/100

o = 21/50

==> o of 250 = p

p = 21/50 × 250

p = (21 × 250)/50

p = 21 × 5

p = 105

==> expressing p as a product of its primes i.e. p = 3 × 5 × q

105 = 3 × 5 × 7

Therefore, q = 7

==> Given a rectangle with dimensions of q cm and r cm, with an area of 56cm². Let's find r.

Area of rectangle = length × width = q × r

Area = 56 cm²

q = 7 cm

r = ?

56 = 7 × r

56/7 = r

8 = r

r = 8 cm

==> r × 0.3 = s

s = 8 × 0.3

s = 2.4

==> s ÷ 0.6 = t

t = 2.4 ÷ 0.6

t = 4

==> If t is in meters, converting t to cm will give us u

Since 1m = 100cm

4m = u cm

1 × u = 100 × 4

u = 400cm

==> Vikki (v) and John shares $u in the ratio 7:3. Thus, Vikki (v) would receive the following:

v = ⁷/10 × $400

v = 0.7 × 400

v = $280

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