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gulaghasi [49]
2 years ago
5

Suppose the length and the width of the sandbox are doubled.

Mathematics
1 answer:
zalisa [80]2 years ago
3 0

The percentage change in perimeter is 100%.

The percentage change in area is 300%

<h3>How to find perimeter and area?</h3>

The perimeter of the sandbox = 2l + 2w

where

  • l = length
  • w = width

Therefore,

perimeter = 2(10) + 2(6)

perimeter = 20 + 12 = 32 ft

The area of the sand box = lw

area = 10 × 6 = 60 ft²

If the length and width are doubled,

length = 2(10) = 20 ft

width = 2(6) = 12 ft

hence,

perimeter = 2(20) + 2(12) = 40 + 24 = 64 ft

area = 12 × 20 = 240 ft²

Therefore,

percentage change in perimeter = 64 - 32 / 32 × 100 = 100%

percentage change in area = 240 - 60 / 60 × 100 = 18000 / 60 = 300%

learn more on perimeter and area here: brainly.com/question/15322533

#SPJ1

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Do one of the​ following, as appropriate.​ (a) Find the critical value z Subscript alpha divided by 2​, ​(b) find the critical v
babymother [125]

Answer:

We want to construct a confidence interval at 99% of confidence, so then the significance level would be 1-0.99 =0.01 and the value of \alpha/2 =0.005. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

z_{\alpha/2}= \pm 2.576

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

Step-by-step explanation:

For this case we have the following info given:

\alpha=0.01, n =26, \sigma = 28.9

We want to construct a confidence interval at 99% of confidence, so then the significance level would be 1-0.99 =0.01 and the value of \alpha/2 =0.005. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

z_{\alpha/2}= \pm 2.576

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

7 0
3 years ago
Hay que envasar 3582 botellas, en donde en cada caja entran 24 botellas. Que
Mariana [72]

Answer:

La operación es de división:

C=3582/24=149.25

Se envasan 149 cajas y quedan 6 botellas para la próxima caja.

The operation is division:

C=3582/24=149.25

149 boxes are completed and 6 bottles are left for the next box.

Step-by-step explanation:

Hay que dividir la cantidad de botellas a envasar (3582) por la cantidad de botellas que entran en cada caja (24).

Esta operación nos da:

C=3582/24=149.25

Podremos llenar 149 cajas por completo, pero nos sobra el contenido de 0.25 cajas, que equivale a 0.25*24=6 botellas.

You have to divide the total amount of bottles (3582) by the amount of bottles per box (24).

Then you have the operation:

C=3582/24=149.25

We can fill 149 complete boxes, but we are left with 0.25 boxes, which is equivalent to 0.25*24=6 bottles.

3 0
3 years ago
15% of an amount is 30?
Alexeev081 [22]

Answer:

200

Step-by-step explanation:

15% × ? = 30

? =

30 ÷ 15% =

30 ÷ (15 ÷ 100) =

(100 × 30) ÷ 15 =

3,000 ÷ 15 =

200

5 0
3 years ago
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The tables shows the low temperature for several days. Which day was the coldest. Picture above
Trava [24]

Answer:

Monday

Step-by-step explanation:

3 0
3 years ago
1/8+c=4/5 what is c? please answer urgent!!!
marshall27 [118]

Answer:

Step-by-step explanation:

1/8 + c = 4/5

c = 4/5 - 1/8

c = 4/5 × 8/8 - 1/8 × 5/5

= <u>32+5 / 40</u>

<u>= 37/40</u>

<u>Hope this helps</u>

<u>plz mark as brainliest!!!!!!</u>

<u />

3 0
4 years ago
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