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Delicious77 [7]
3 years ago
6

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! Factor.

Mathematics
2 answers:
AURORKA [14]3 years ago
7 0

20xy-4y+35x-7=4y(5x-1)+7(5x-1)=(5x-1)(4y+7)

Alex787 [66]3 years ago
6 0
5x(4y+7)-1(4y+7)

(5x-1)(4y+7)
You might be interested in
(a) Let R = {(a,b): a² + 3b <= 12, a, b € z+} be a relation defined on z+)
grin007 [14]

Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

Therefore, R is reflexive

If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

brainly.com/question/1503196

4 0
2 years ago
Please help me i need help pls
OverLord2011 [107]

Answer:

see explanation

Step-by-step explanation:

(b)

30n - 12 ( factor out the gcf 6 from each term )

= 6(5n - 2) ← in factored form

(c)

6x + 9y ( factor out the gcf 3 from each term )

= 3(2x + 3y) ← in factored form

6 0
2 years ago
2x + 4 / 3 = -8 please help
arsen [322]
X= -14/3 !


hope this helps
4 0
2 years ago
Read 2 more answers
The length and width of a rectangular park are determined by the polynomials (3x+4) and (2x−3). What is the perimeter of the par
ipn [44]

Answer:

tree? heh

Step-by-step explanation:

7 0
3 years ago
24 + 28 as a product of two factors using the GCF and distributive property
Yakvenalex [24]

Answer:

52

Step-by-step explanation:

Using GCF:

The factors of 24 are; 1, 2, 3, 4, 6, 8, 12, 24

Factors of 28 are; 1, 2, 4, 7, 14, 28

The highest greatest common factor is 4.

Now, 4 × 6 gives 24

While 4 × 7 gives 28.

Thus, our original equation is now;

4(6 + 7)

Using distributive property, let's add the number in the bracket first to get;

4(13).

Now,we multiply out to get 52.

8 0
3 years ago
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