To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
Sandwich cost $7.70 and the soda costs $2.20.
Answer:
The domain is -7, 0, and 5
The range is -1, 0, and 8
Step-by-step explanation:
The domain of a set of points is the x-value. In this case the x-values are -7, 0, and 5 respectively. The range of a set of points is the y-value so in this case the range is -1, 0, and 8.
Answer:
-3q² + 3qp + 2rp - 2rq + Sq - Sp
Step-by-step explanation:
first part
3q(p-q) = 3qp - 3q²
second part
2r(p-q) = 2rp - 2rq
third part
S(q-p) = Sq - Sp
then we put it all together
3qp - 3q² + 2rp - 2rq + Sq - Sp
in the right place possibly
-3q² + 3qp + 2rp - 2rq + Sq - Sp