Question

The number of bacteria in petri dish A doubles every 10 minutes. The number of bacteria in oetri dish B doubles every 6 minites. If both petri dishes begin with the same number of bacteria, how mmau times greater will the number of bacteria in petri dish b be than the number of bacteria in petri dish A after one hour?

Answer 1

Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes

Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.

Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10

A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B

B/A = 102400 / 6400 = 16

There are 16 times as many in B than in A. <<<< Answer