Answer:
1 La longitud de las nuevas cuerdas = 5 metros y 9 metros
2 El costo de las paletas = $ 3
El costo de las gomitas = $ 3
Step-by-step explanation:
1) Sea la primera mitad de la cuerda representada por = a
Deje que la segunda mitad de la parte superior esté representada por = b
a + b = 14 metros
De la pregunta, se nos dice que ok, la mitad es 4 metros más larga que la otra
a = b + 4
Por lo tanto
b + 4 + b = 14 metros
2b + 4 = 14 metros
2b = 14 - 4
b = 10/2
b = 5 metros
a = b + 4
a = 5+ 4
a = 9 metros
Por lo tanto, la longitud de las nuevas cuerdas = 5 metros y 9 metros
2)
Representemos el costo de las paletas = p
Costo de gomitas = g
De la pregunta 2 se nos dice que:
Tu vas a la tienda con un amigo y compras 6 paletas y 2 gomitas. Si tú pagas $ 24
Por tanto: 6p + 2g = 24 ....... Ecuación 1
Tu amigo pide 1 paleta y 10 gomitas. y tu amigo $ 33
p + 10g = 33 ....... Ecuación 2
p = 33 - 10g
Sustituya p por 33 - 10g en la Ecuación 1
6p + 2g = 24 ....... Ecuación
6 (33-10 g) + 2 g = 24
198 - 60 g + 2 g = 24
-58g = 24-198
-58g = - 174
g = -174 / -58
g = $ 3
Para encontrar p
p = 33 - 10g
p = 33 - 10 × 3
p = 33 - 30
p = $ 3
Por lo tant,
El costo de las paletas = $ 3
El costo de las gomitas = $ 3
Answer:
-24
Step-by-step explanation:
goes by -5
Answer:
0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
What is the probability that a randomly generated value of X is greater than a randomly generated value of Y
This means that the subtraction of X by Y has to be positive.
When we subtract two normal variables, the mean is the subtraction of their means, and the standard deviation is the square root of the sum of their variances. So
We want to find P(X > 0), that is, 1 subtracted by the pvalue of Z when X = 0. So
has a pvalue of 0.0228
1 - 0.0228 = 0.9772
0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y
Answer:
Prime numbers are numbers that cannot be divided into further whole numbers. You cannot divide 19 and 13 because 13 and 19 are already prime numbers.
Step-by-step explanation:
