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Kruka [31]
3 years ago
13

Two bicycles are driving on the circle in the same direction with speeds of 9 mph and 5 mph respectively. How many points are th

ere on the circle where the two bicycles meet.
Mathematics
1 answer:
pychu [463]3 years ago
4 0

Given that,

Speed of first bicycle = 9 mph

Speed of second bicycle = 5 mph

Suppose the length of the circle 24 miles.

We need to find the relative velocity

Using formula of relative velocity

v=v_{1}-v_{2}

Put the value into the formula

v=9-5

v=4\ mph

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

t=\dfrac{24}{4}

t=6\ hr

We need to calculate the distance of the points where the two bicycles meet

Using formula of distance

For first bicycles,

d=9\times6

d=54\ miles

For second bicycles,

d'=5\times6

d'=30\ miles

Hence, The points where the two bicycles meet after every 6hr at 30 miles and 54 miles.

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How do you solve this?
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Answer:

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The graph in the attached figure

Step-by-step explanation:

Let

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Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution is the point (8,16)

see the attached figure

therefore

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We can apply the following properties of radicals:

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Then, we have:

\begin{gathered} \text{ Apply the product property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7}{8}\cdot\frac{7}{18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7\cdot7}{8\cdot18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{49}{144}} \\ \text{ Apply the quotient property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{\sqrt[]{49}}{\sqrt[]{144}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{7}{12} \end{gathered}

Therefore, the choice that is equivalent to the given product is:

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4 0
1 year ago
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rosijanka [135]
X is undefined.

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Answer:

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