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stepan [7]
3 years ago
12

How do you write 984 in scientific notation

Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Answer: 9.84 x 10²

Step-by-step explanation: To write 984 in scientific notation, first write a decimal point in the number so that there is only one digit to the left of the decimal point.

So here we have 9<em>.</em>84.

Next, count the number of places that we would need to move the decimal point in 9<em>.</em>84 in order to get back to the original number, 984.

Since we would need to move the decimal point two places to the right to get back to the original number, we have an exponent of 2.

Notice that our exponent is positive because we would need to move the decimal point to the right.

Now, scientific notation is always expressed as a power of 10. In this case, we have 10 to the 2nd or 10 to the 2nd power.

So 984 can be written in scientific notation as 9.84 x 10².

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Mixed Number Form: 6 11/45
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mario62 [17]

Step-by-step explanation:

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6 0
3 years ago
The base of a solid is the region enclosed by the graphs of y=e^x, y=0, x=0, and x = 1. If each cross-section perpendicular to t
yanalaym [24]

Answer:

A

Step-by-step explanation:

The base of a solid in the region enclosed by the graphs of <em>y</em> = eˣ, <em>y</em> = 0, <em>x </em>= 0, and <em>x</em> = 1. Each cross-section perpendicular to the <em>x</em>-axis is an equilateral triangle. We want to find the volume of the solid.

Please refer to the graph below. We are concerned with the red region.

In order to find the volume, we essentially sum up the area of the figure at each <em>x</em> value. So, we integrate from <em>x </em> = 0 to <em>x </em>= 1.

The area for an equilateral triangle is given by:

\displaystyle A=\frac{\sqrt{3}}{4}s^2

Where <em>s</em> is the side length of the triangle.

Since the triangle lies perpendicular on the region, the side length of the triangle at <em>x</em> is simply <em>y</em>, which is eˣ.

Therefore, our volume is:

\displaystyle V=\int_0^1\frac{\sqrt3}{4}(y)^2\, dx

Substitute:

\displaystyle V=\int_0^1\frac{\sqrt3}{4}(e^x)^2\, dx

Evaluate the integral. Simplify:

\displaystyle V=\frac{\sqrt3}{4}\int_0^1e^{2x}\, dx

Integrate using u-substitution:

\displaystyle V=\frac{\sqrt3}{8}\left(e^{2x}\Big|_0^1\right)

Evaluate:

\displaystyle V=\frac{\sqrt3}{8}\left(e^{2(1)}-e^{2(0)} \right)

Therefore, the volume of the solid is:

\displaystyle V=\frac{\sqrt3}{8}\left(e^2-1\right)

Our answer is A.

3 0
3 years ago
Read 2 more answers
Solve for x: 5x + 2 = 4x − 9.<br><br> 7<br> −7<br> 11<br> −11
irinina [24]
Simple....

you have:

5x+2=4x-9

5x+2=4x-9
-4x         -4x

x+2=-9

x+2=-9
   -2  -2

x=-11

Thus, your answer.
7 0
3 years ago
Read 2 more answers
The ages of the 32 recruits in police academy are normally distributed with a mean of 27 with a standard deviation of 2. What is
aksik [14]
Since it's a sample size, we use x, as the mean and s= standard deviation
            _
Given:  x =27, s = 2 and total sample = 32.
Probability that a recruit is at least 31 years old?

Let's calculate the Z score :
              _
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Z = ----------- → Z = -------- → Z = 2 (now look up in the Z score table,
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Area (Z=2) =0.9772 , but Z ≥ 2  (at least) , then :
Area (Z≥2) = Area (Z≤ - 2)  = 0.0228

P(≥31)= 0.0228
7 0
3 years ago
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