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kakasveta [241]
3 years ago
13

It costs $3 for a pack of 20 pencils. Find the cost per pencil.

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0

Answer:

20/3

Step-by-step explanation:

notsponge [240]3 years ago
3 0

Answer:

15 cents right?

Step-by-step explanation:

3/20=.15

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Mr. And Mrs. Doran have a genetic history such that the probability that a child being born to them with a certain trait is 0.14
poizon [28]

Answer:

0.938

Step-by-step explanation:

From the question :

p = 0.14

Number of children, n = 7

P(x ≤ 2) = P(2) + P(1) + P(0)

Using binomial probability :

P(x =x) = nCx  * p^x * (1 - p)^(n - x)

We could also use the binomial probability calculator :

P(x ≤ 2) = 0.3479 + 0.3965 + 0.1936

P(x ≤ 2) = 0.938

8 0
3 years ago
Fifty 6th grade students chose to play outside for free time. This is 25% of the 6th grade class. How many total students are th
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Answer- 200

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3 years ago
Lucy has a strawberry lace that is 36cm long. She needs pieces 18mm long to decorate a cake. How long is the 36cm one in mm
KonstantinChe [14]
The strawberry lace is 36 cms long.
36 cms = 360 mm
(Because we multiply by 10, when we convert from cm to mm).
7 0
3 years ago
Read 2 more answers
En un aeropuerto dos aviones A1 y A1 se acercan para aterrizar, si la ecuación de la trayectoria del primero es -x+2y-100=0, mie
liraira [26]

No hay solución en la que ambas trayectorias estén en la misma posición, puesto que no existe el riesgo de que sufran un choque entre ellos.

-------------------------

La trayectoria del primero es:

-x + 2y - 100 = 0

x_1 = 2y - 100

Para el segundo, tiene-se que:

-x + 200 + 2y = 0

x_2 = 2y + 200

Igualando los valores de x:

x_1 = x_2

2y - 100 = 2y + 200

0y = 300

No hay solución en la que ambas trayectorias estén en la misma posición, puesto que no existe el riesgo de que sufran un choque entre ellos.

Un problema similar es dado en brainly.com/question/24653364

3 0
3 years ago
Please help me with my hw thank you so much
Yuri [45]

Answer: d

Step-by-step explanation:

8 0
3 years ago
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