Answer:

Step-by-step explanation:
The generating function a(x) produces a power series ...

where the coefficients are the elements of the given sequence.
We observe that the given sequence has the recurrence relation ...

This can be rearranged to ...

We can formulate this in terms of a(x) as follows, then solve for a(x).

The generating function is ...
a(x) = 1/(1+2x)
It’s 6
since it’s right at 5 & 7
http://www.mathopenref.com/coordintro.html
http://www.cpalms.org/Public/PreviewResourceAssessment/Preview/70464
Answer:
24, 64
Step-by-step explanation:
If I add 1 to a multiple of 8 I get a multiple of 5, what multiples of 8
meet the condition? (Mention at least 2 of them)
3 x 8 + 1 = 25
8 x 8 + 1 = 65
The percentage would be about 64%