Question

What is the discriminant of 32x-4= 4x^2 + 60

Answer 1

Step One

Begin by getting one side of the question equal to zero.

32x -4 = 4x^2 + 60 Add - 32x + 4 from both sides.

0 = 4x^2 + 60 - 32x + 4 Collect like terms.

0 = 4x^2 - 32x + 64

Step Two

For this question, you could divide both sides by 4. It just makes the steps later on easier.

0 = x^2 - 8x + 16

Step Three

Calculate the discriminate.

The discriminate is b^2 - 4*a*c

a = 1; b = -8; c = 16

b^2 - 4*a*c = (-8)^2 - 4*(1)(16) = 64 - 64 = 0

There is only 1 root. It is real and it is rational.

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