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EleoNora [17]
3 years ago
15

Graph the ordered pairs for y = 4x + 2 using {-2,1,2}

Mathematics
1 answer:
deff fn [24]3 years ago
3 0
No clue there has to be a graph paper for the answer
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SUPPOSE 3 FRIENDS WANT TO SHARE 16 POSTERS EQUALLY. FOR THIS SITUATION, WHY DOES THE QUOTIENT 5 R1 MAKE MORE SENSE THAN THE QUOT
Vikentia [17]

Because normally you don't cut posters into thirds. You keep them as whole numbers therefore fractions make no sense

6 0
3 years ago
What type of function is y=7(5/4)^x
erica [24]

Answer:

It is a equation

Step-by-step explanation:

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4 0
4 years ago
Please i need help realy fast or i will fail this semester
katrin2010 [14]
Y=mx+b
m=slope
b=yintercept

given
y=-2x+3 and
y=-4x-1

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3rd option
8 0
4 years ago
Read 2 more answers
Initially 5 grams of salt are dissolved into 10 liters of water. Brine with concentration of salt 5 grams per liter is added at
DiKsa [7]

Salt flows in at a rate of (5 g/L)*(3 L/min) = 15 g/min.

Salt flows out at a rate of (x/10 g/L)*(3 L/min) = 3x/10 g/min.

So the net flow rate of salt, given by x(t) in grams, is governed by the differential equation,

x'(t)=15-\dfrac{3x(t)}{10}

which is linear. Move the x term to the right side, then multiply both sides by e^{3t/10}:

e^{3t/10}x'+\dfrac{3e^{t/10}}{10}x=15e^{3t/10}

\implies\left(e^{3t/10}x\right)'=15e^{3t/10}

Integrate both sides, then solve for x:

e^{3t/10}x=50e^{3t/10}+C

\implies x(t)=50+Ce^{-3t/10}

Since the tank starts with 5 g of salt at time t=0, we have

5=50+C\implies C=-45

\implies\boxed{x(t)=50-45e^{-3t/10}}

The time it takes for the tank to hold 20 g of salt is t such that

20=50-45e^{-3t/10}\implies t=\dfrac{20}3\ln\dfrac32\approx2.7031\,\mathrm{min}

3 0
3 years ago
Jamal hiked on two trails the 1st trail was 5 1/3 miles long and the 2nd trail was 1 3/4 time as long as the 1st trail how many
lisov135 [29]
5 1/3 + 1 3/4(5 1/3) = 16/3 + 7/4(16/3) = 16/3 + 28/3 = 44/3 or 14 2/3 <==
5 0
4 years ago
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