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kondor19780726 [428]
3 years ago
12

Please Explain Why!

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
5 0

The answer is A :) Hope this helps

Digiron [165]3 years ago
4 0

This looks like were trying to prove a pair of angles of an isosceles triangle are congruent.

To do that we need the fact that it's an isosceles triangle, which is AB=AC.

That's choice A.

None of the other choices make sense just by symmetry. AD=AC, nope the middle and the side, BD=AD, nope, AB=BD, nope.

choice A.

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Simplify.<br> Rewrite the expression in the form z^n<br> z^7/z^-14<br> =<br> 21
beks73 [17]

Step-by-step explanation:

z^7/z^-14=21

z^21=21

5 0
2 years ago
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Multiple choice please answer please
tankabanditka [31]

Answer:

B.cos^{-1} \bigg(\frac{4}{5}\bigg)

Step-by-step explanation:

\because \cos \angle B = \bigg(\frac{4}{5}\bigg)\\\\\therefore  \angle B =cos^{-1} \bigg(\frac{4}{5}\bigg)\\

3 0
3 years ago
What is the length of the segment with end points -3,4 and 5,4
Luda [366]

Answer:

8

Step-by-step explanation:

The distance or the length between two points can be computed using the formula:

d = \sqrt{(X_2-X_1)^2+(Y_2-Y_1)^2}

X₁ = x-coordinate of first point

X₂ = x-coordinate of the second point

Y₁ = y-coordinate of first point

Y₂ = y-coordinate of the second point

When we right down the coordinates of a point, we always start with the X and then the Y.

(X,Y)

You have the following coordinates or points

Point 1: (-3,4)

Point 2: (5,4)

Based on that we have the following given:

X₁ = -3

X₂ = 5

Y₁ = 4

Y₂ = 4

Now we just fill in the formula:

d=\sqrt{(X_2-X_1)^2+(Y_2-Y_1)^2}\\\\ =\sqrt{(5-(-3))^2+(4-4)^2}\\\\ =\sqrt{8^2 + 0^2}\\\\ =\sqrt{8^2} \\\\=8

7 0
3 years ago
In the expression -5g12 which part is the base?
Montano1993 [528]
-5 is the base of -5g in this expression
5 0
3 years ago
Suppose that you had two squares, a small one and a large one. The area of the large square is twice that of the small square. H
WARRIOR [948]

Answer:

The side length of the large square is √2 times larger than the side length of the small square.

Step-by-step explanation:

Suppose we have a small square (square 1) and a large square (square 2). The area of the large square is twice that of the small square, that is,

A₂ = 2 A₁

A₂/A₁ = 2 [1]

The area of a square is equal to the length of the side (l) raised to the second power.

A = l²

l = √A

The ratio of l₂ to l₁ is:

l₂/l₁ = √A₂ / √A₁ = √(A₂/A₁)

We can replace [1] in the previous expression.

l₂/l₁ = √2

The side length of the large square is √2 times larger than the side length of the small square.

7 0
3 years ago
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