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tresset_1 [31]
3 years ago
7

Help usatestprep need answer

Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0

Answer:

one solution

Step-by-step explanation:

they only meet up once

get a new computer br.uh

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Keith bought a desktop computer and a laptop computer. Before finance charges, the laptop cost $150 more than the desktop. He pa
ss7ja [257]

Answer: desktop = $1750, laptop = $1900

<u>Step-by-step explanation:</u>

Let x represent the cost of the desktop

then x + 150 is the cost of the laptop.

.07x + .055(x + 150) = 227

.07x + .055x + 8.25 = 227

.125x = 218.75

x = 1750

desktop (x) = $1750

laptop (x + 150) = $1750 + $150 = $1900

5 0
3 years ago
What is the Slope of a line that passes through the points (-3,5) and (1,7) ?
Naya [18.7K]
Find the change in the y coordinates

7-5=2

Find the change in the x coordinates 

1--3 or 1+3= 4

Divide the changes in the y and x coordinates

2/4= 1/2

The slope is 1/2. Hope this helps!
6 0
3 years ago
Read 2 more answers
TJ invested $4000 in a bond at a yearly rate of 2% for 30
slavikrds [6]

Answer:

2.5 years

Step-by-step explanation:

I = 200     T=200/4000 0.2  = 2.5 years

P= 4000

R = 2%  0.2

T = ?  

4 0
3 years ago
Determine if a slope of two consecutive sides are parallel or neither? ​
inessss [21]

Answer:

No

Step-by-step explanation:

Two consecutive sides means that the two sides are connected in a shape by a vertex. If the sides were parallel, they would have to be right on top of each other, so two consecutive sides cannot be parallel.

3 0
4 years ago
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
3 years ago
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