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Anna [14]
2 years ago
12

4) How many total hours does Terry work for the week if she works 3 hrs.

Mathematics
1 answer:
Juliette [100K]2 years ago
5 0

Answer:

32 hours and 55 minutes

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HELP.... square root of y5
dmitriy555 [2]
Sqrt (y^4 * y)
Sqrt y*4 = y^2
y^2 sqrt y
4 0
3 years ago
Josh paid $11.96 for a 2.24 -pound bag of shrimp at one store. The following week, he paid $17.24 for a 3.12 -pound bag at anoth
Whitepunk [10]
The first bag would be 5.34$ and the second would be 5.53$ and the second bag is better cause your only spending 19 more cents for 1.5 more pounds
6 0
3 years ago
X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
1 year ago
Determine the equation of the line that is perpendicular to the line y = 3x + 4 and passes through the point (6, 2).
fomenos

Answer:

y = -1/3x + 4

Step-by-step explanation:

Perpendicular lines: Their gradients are reciprocals.

This means:

  • -1 ÷ Gradient 1 = Gradient 2
  • Gradient 1 * Gradient 2 = -1

Gradient of the given equation is 3.

-1 / 3 = -1/3

Gradient of the equation we're finding is -1/3

y = -1/3x + c

Substitute the coordinates in to find the value of c

2 = -1/3(6) + c

2 = -2 + c

2 + 2 = c

4 = c

y = -1/3x + 4

3 0
2 years ago
What is the estimated quotient of 57.8/81
Brut [27]
The answer to this is : 0.75 (.75) 




4 0
3 years ago
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