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vlabodo [156]
3 years ago
7

Find the domain of f(x)=square root x^2−36.

Mathematics
1 answer:
vichka [17]3 years ago
5 0
f(x)= \sqrt{x^{2}-36}   \\  \\ D: x^{2}-36 \geq 0 \\  \\ (x-6)(x+6)  \geq 0 \\  \\ x+6=0 \ \vee \ x-6=0 \\  \\ x=-6 \ \vee \ x=6 \\  \\ x\in (-\infty,-6 ) \ \cup \ (6,+\infty)
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0 = 4 + n/5 two step equations​
Serjik [45]

Answer: n= -20?

Step-by-step:

Simplify both sides of the equation

1/5n+4=0

Then subtract 4 from both sides

1/5n + 4 - 4 = 0 - 4

1/5n= -4

Then multiply both sides by 5

5*(1/5n)=5*(-4)

5 0
3 years ago
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Can someone actually answer this question pls its my 3rd time posting it and ill ive gotten was wrong or answers that make no se
andre [41]

Answer:

(-2+-5) equals -7.

Because the signs are the same, we dont change it.

(3+5) equals 8. Same like the other equation, the signs are the same so we do not change it.

Now we do (-7+8) The answer will be 1. Lets use a little graph since its hard to explain.

-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8

Mark -7 anyway you want. (Circle it, draw a line under it, what ever you want.)

Now Move the line 8 times.

When you do that your line will stop at 1.

And thats how you do it.

Step-by-step explanation:

7 0
3 years ago
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What of the following exponential functions is represented by the data in the table?
patriot [66]

Answer:

f(x) = ( 1/3) ^ (x)

Step-by-step explanation:

The function is

f(x) = (1/3) ^ (x)

When x = 1  f(x) = 1/3

when x=2    f(x) = 1/9

When x = -1  f(x) = ( 1/3) ^ -1 = 3/1 =3

7 0
2 years ago
3. Here is a diagram of a softball field:
Crank

a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.

b. The area of the outfield is about 39,584 sq. ft..

<h3>What is the Perimeter of a Quarter Circle?</h3>

Perimeter of circle = 2πr

Perimeter of a quarter circle = 2r + 1/4(2πr).

a. The length of the fence around the field = perimeter of the quarter circle fence

= 2r + 1/4(2πr).

r = 250 ft

Plug in the value

The length of the fence around the field = 2(250) + 1/4(2 × π × 250)

= 892.7 ft.

b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)

= 1/4(πR²) - πr²

R = radius of the full field = 250 ft

r = radius of the infield = 110/2 = 55 ft

Plug in the values

Size of the outfield = 1/4(π × 250²) - π × 55²

= 49,087 - 9,503

= 39,584 sq. ft.

Learn more about perimeter of quarter circle on:

brainly.com/question/15976233

4 0
2 years ago
Solve the equation<br> v² = 24
drek231 [11]

Answer:

v=6

v=−4

Step-by-step explanation:

8 0
3 years ago
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