Question

Find the domain of f(x)=square root x^2−36.

Answer 1

$f(x)= \sqrt{x^{2}-36} \\ \\ D: x^{2}-36 \geq 0 \\ \\ (x-6)(x+6) \geq 0 \\ \\ x+6=0 \ \vee \ x-6=0 \\ \\ x=-6 \ \vee \ x=6 \\ \\ x\in (-\infty,-6 ) \ \cup \ (6,+\infty)$