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vlabodo [156]
2 years ago
7

Find the domain of f(x)=square root x^2−36.

Mathematics
1 answer:
vichka [17]2 years ago
5 0
f(x)= \sqrt{x^{2}-36}   \\  \\ D: x^{2}-36 \geq 0 \\  \\ (x-6)(x+6)  \geq 0 \\  \\ x+6=0 \ \vee \ x-6=0 \\  \\ x=-6 \ \vee \ x=6 \\  \\ x\in (-\infty,-6 ) \ \cup \ (6,+\infty)
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3 years ago
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Keith_Richards [23]

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_____

The graph shows this polynomial has the required zeros.

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