Answer:
y = -2x - 10
Step-by-step explanation:
Slope intercept form of equation is of form
y = mx+c
where m is the slope of line and c is the y intercept of the line.
Y intercept is point on y axis where the line intersects the y axis.
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Given equation
y = -2x +4
comparing it with y = mx+ c
m = -2 , c = 4
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when two lines are parallel, their slopes are equal.
Let the equation of new line in slope intercept form be y = mx + c
Thus slope of of new required line is -2
Thus m for new line is -2.
now, equation of required line : y = -2x+c
Given that this line passes through (-4, -2). This point shall should satisfy equation y = -2x+c.
Substituting the value of (-4, -2) we have
-2 = -2(-4)+c
=> -2 = 8 +c
=> -2 -8 = c
=> c = -10.
Thus , equation of required line is y = -2x - 10.
Answer:
x>-1
Step-by-step explanation:
Answer:
See in attachment and Mark as brainleist please.
Answer:
y=3/2x+11/2
Step-by-step explanation:
Hello! Sorry I just saw this
Anyways, let's continue
first, we need to find the equation of the line with the one that is (-2,-4) and (2,2)
first, we need to find the slope
the equation for slope is y2-y1/x2-x1
so let's label the points
x1=-2
y1=-4
x2=2
y2=2
now plug it in
2-(-4)/2-(-2)=6/4=3/2
now, let's turn it into a line
the point-slope form is y-y1=m(x-x1) (m=slope)
now, plug it in
y-(-4)=3/2(x-(-2))
simplify to
y+4=3/2(x+2)
turn into y=mx+b format
y+4=3/2x+3
subtract 4 on both sides
y=3/2x-1
Now for the line that is parallel.
Parallel lines have the same slopes, so you automatically know that the new line will be y=3/2x+b
To make sure (-3,1) is a solution to the point, put 1 as y and -3 as x
1=3/2(-3)+b
1=-9/2+b
add 9/2 on both sides
b=11/2 or 5.5
now, put it into the equation
y=3/2x+11/2
Hope this helps!
