1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
scZoUnD [109]
3 years ago
6

Do natural numbers have multiplicative inverse

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0
No,because a multiplcative inverse is when your changing a division or multiplcation sign!
You might be interested in
Identify the domain of the function shown in the graph.
OverLord2011 [107]
The domain of the function would be -5
Th answer is would be D
5 0
3 years ago
Please answer with clear instructions so that i can apply this to other questions
Mrrafil [7]

Answer:

1/6

Step-by-step explanation:

-1/m

-1/-6

1/6

4 0
2 years ago
An airplane descends from 15,000 feet at a rate of 200 feet per second.
Sauron [17]

Answer:

The answer should B, only one makes sense

7 0
2 years ago
Read 2 more answers
Jim earns a regular hourly rate
AveGali [126]
I'm glad to hear that, but where is the math problem?
4 0
2 years ago
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
Other questions:
  • Plz help
    14·1 answer
  • Could you find the greatest common multiple of two numbers?
    8·1 answer
  • How do you translate a figure 5 units right and 1 unit up, what are the coordinates ?
    10·2 answers
  • What is the answer to -7x + x?
    13·2 answers
  • For the function f(x)=x+9/7-4x find f^-1(x)
    15·1 answer
  • (5x - 2y = 22<br> 8x - 2y = 28<br><br> Please!! Urgent
    12·1 answer
  • 6 less than n is greater than 8​
    10·1 answer
  • 13=d÷6 Solve this pleaseeeee
    12·1 answer
  • If the simple interest on $7,000 for 2 years is 980, then what is the interest rate?
    6·1 answer
  • (x - 3 ) ( 6x -2)<br><br> help plz
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!