Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Parallel lines always have the same slope

1) Determine the slope of line S using line R (m)

$y=-\frac{1}{4} x+3$

We can identify clearly that the slope of the line is $-\frac{1}{4}$ , as it is in the place of m. Because parallel lines always have the same slope, the slope of line S would also be $-\frac{1}{4}$ . Plug this into $y=mx+b$ :

$y=-\frac{1}{4}x+b$

2) Determine the y-intercept of line S (b)

$y=-\frac{1}{4}x+b$

Plug in the given point (-4,3) and solve for b

$3=-\frac{1}{4}(-4)+b\\3=1+b$

Subtract 1 from both sides to isolate b

$3-1=1+b-1\\2=b$

Therefore, the y-intercept is 2. Plug this back into $y=-\frac{1}{4}x+b$ :

$y=-\frac{1}{4}x+2$

I hope this helps!

6 0

2 years ago

Genrish500 [490]

Answer:

to be fair this looks hard but i can do just give me five mins

Step-by-step explanation:

8 0

2 years ago