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Shkiper50 [21]
3 years ago
14

Compare the weather on two different days using an inequality. Then see if their comparisons change by finding the absolute valu

e of each.
Day 1:
Day 2:
Mathematics
2 answers:
dusya [7]3 years ago
7 0

Inequalities are used to compare unequal expressions.

The actual comparison is:\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

The temperatures are given as:

\mathbf{Temperature =  -3.5F,\ \  5F,\ \  1.5F,\ \  -0.5F,\ \ -2F,\  \ 2.5F,\ \  -4F}

From the above list, we have:

\mathbf{Day \ 1=  -3.5F}

\mathbf{Day \ 2=  5F}

By comparison,

\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Using absolute values, the inequalities are:

\mathbf{|-3.5| < |5|} or \mathbf{|5| > |-3.5|}

Hence, the actual comparison is:

\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Read more about inequalities and absolute values at:

brainly.com/question/24797699

Olin [163]3 years ago
6 0

Answer:

sorry po talaga.. kung iniísip nyô na nàkaw points ako..nàwala po kase acc ko eh

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The store sells walnuts for $2.95 per pound. Corey bought 2.4 pounds of walnuts. Before tax, how much will the walnuts cost?
stepladder [879]

Answer:

$7.18

Step-by-step explanation:

Multiply the number of pounds bought by the cost of one pound.

 (2.4 pounds)($2.99 per pound) = $7.176 ≅ $7.18

7 0
3 years ago
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The sum of three consecutive odd numbers is 987. Find the numbers.
hodyreva [135]

Answer:

Step-by-step explanation:

Let first odd number = a, second odd number = a +2, third odd number = a + 4

a + a + 2 + a + 4 = 987

3a + 6 = 987

3a = 981

a = 327

First odd number = a = 327

Second odd number = a + 2 = 329

Third odd number = a + 4 = 331

6 0
3 years ago
Find the areas of the trapezoids.
Juliette [100K]

Answer:

12 square units

Step-by-step explanation:

A = 1/2·h(sum of bases)

A = 1/2(4)(2+4)

A = 2(6) which is 12 square units

3 0
3 years ago
Who can help me with number 14
Rzqust [24]
(Original Price $425.4)

$328 × 30% = 98.4
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5 0
4 years ago
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Ill give you Brainlyest! I need help ASAP work shown, please!!<br> problems 8-15
8_murik_8 [283]

Using the segment addition theorem, the solutions are:

5. x = 17

6. x = 7

7. x = 14

BC = 27

CD = 61

BD = 88

8. AB = 26

9. LJ = 46

10. x = 3

11. FG = 15

12. QS = 34

13. BC = 26

14. EG = 19

15. QS = 68

<h3>How to Apply the Segment Addition Theorem?</h3>

The segment addition theorem would be used to solve the problems as shown below:

5. UW = UV + VW [segment addition theorem]

Substitute

6x - 35 = 19 + 4x - 20

6x - 4x = 35 + 19 - 20

2x = 34

x = 17

6. HJ = HI + IJ [segment addition theorem]

Substitute

7x - 27 = 3x - 5 + x - 1

7x - 3x - x = 27 - 5 - 1

3x = 21

x = 7

7. BD = BC + CD [segment addition theorem]

Substitute

7x - 10 = 4x - 29 + 5x - 9

7x - 4x - 5x = 10 - 29 - 9

-2x = -28

x = 14

BC = 4x - 29 = 4(14) - 29 = 27

CD = 5x - 9 = 5(14) - 9 = 61

BD = 7x - 10 = 7(14) - 10 = 88

8. BC = BD

Substitute

2x + 1 = 5x - 26

2x - 5x = -1 - 26

-3x = -27

x = 9

AB = 43 - BC

AB = 43 - 2x + 1 = 43 - 2(9) + 1 = 26

9. 7x - 10 = 9x - 11 - (x + 3)

7x - 10 = 9x - 11 - x - 3

7x - 9x + x = 10 - 11 - 3

-x = -4

x = 4

LJ = 28 + 7x - 10 = 28 + 7(4) - 10

LJ = 46

10. 8x + 11 = 12x - 1

8x - 12x = -11 - 1

-4x = -12

x = 3

11. 11x - 7 = 3x + 9

11x - 3x = 7 + 9

8x = 16

x = 2

FG = 11x - 7 = 11(2) - 7

FG = 15

12. 5x - 3 = 21 - x

5x + x = 21 + 3

6x = 24

x = 4

QS = 2(5x - 3) = 10x - 6 = 10(4) - 6

QS = 34

13. 8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

8x - 6x = 20 - 2

2x = 18

x = 9

BC = AB = 3x - 1 = 3(9) - 1

BC = 26

14. 5x - 1 = 7x - 13

5x - 7x = 1 - 13

-2x = -12

x = 6

EG = 6x - 4 - 13 = 6(6) - 4 - 13

EG = 19

15. RT - ST = RS

Substitute

8x - 43 - (4x - 1) = 2x - 4

8x - 43 - 4x + 1 = 2x - 4

4x - 42 = 2x - 4

4x - 2x = 42 - 4

2x = 38

x = 19

QS = 2(RS)

QS = 2(2x - 4) = 4x - 8 = 4(19) - 8

QS = 68

Learn more about the segment addition theorem on:

brainly.com/question/28263183

#SPJ1

8 0
2 years ago
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