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Shkiper50 [21]
3 years ago
14

Compare the weather on two different days using an inequality. Then see if their comparisons change by finding the absolute valu

e of each.
Day 1:
Day 2:
Mathematics
2 answers:
dusya [7]3 years ago
7 0

Inequalities are used to compare unequal expressions.

The actual comparison is:\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

The temperatures are given as:

\mathbf{Temperature =  -3.5F,\ \  5F,\ \  1.5F,\ \  -0.5F,\ \ -2F,\  \ 2.5F,\ \  -4F}

From the above list, we have:

\mathbf{Day \ 1=  -3.5F}

\mathbf{Day \ 2=  5F}

By comparison,

\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Using absolute values, the inequalities are:

\mathbf{|-3.5| < |5|} or \mathbf{|5| > |-3.5|}

Hence, the actual comparison is:

\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Read more about inequalities and absolute values at:

brainly.com/question/24797699

Olin [163]3 years ago
6 0

Answer:

sorry po talaga.. kung iniísip nyô na nàkaw points ako..nàwala po kase acc ko eh

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Alicia's brother is three years younger than twice her age. The sum of their ages is 24. How old is Alicia?
Alborosie
9 because 24 divided by 2 is 12 and 12 subtracted by 3 is 9
5 0
3 years ago
A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po
astra-53 [7]

Answer:

a. See Attachment 1

b. PT = 12.3\ m

c. HT = 31.1\ m

d. OH = 28.4\ m

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OT}{20}

Multiply both sides by 20

20 * tan50 = \frac{OT}{20} * 20

20 * tan50 = OT

20 * 1.1918 = OT

23.836  = OT

OT = 23.836

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

tan30 = \frac{OP}{20}

Multiply both sides by 20

20 * tan30 = \frac{OP}{20} * 20

20 * tan30 = OP

20 * 0.5774= OP

11.548 = OP

OP = 11.548

PT = OT - OP

PT = 23.836 - 11.548

PT = 12.288

PT = 12.3\ m (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

HT^2 = OT^2 + OH^2

Substitute 20 for OH and OT = 23.836

HT^2 = 20^2 + 23.836^2

HT^2 = 400 + 568.154896

HT^2 = 968.154896

Take Square Root of both sides

HT = \sqrt{968.154896}

HT = 31.1\ m <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

OT * tan50 = {OH

OT * 1.1918 = OH

Substitute OT = 23.836

23.836 * 1.1918 = OH

28.4= OH

OH = 28.4\ m<em> (Approximated)</em>

5 0
2 years ago
IM / TTM Lesson , please help
baherus [9]
Where’s the question?
5 0
2 years ago
Given : 11x – 6y = –1; x = 8
Natasha_Volkova [10]

Answer:

B. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Division Property of Equality; e. Symmetric Property of Equality

Step-by-step explanation:

Given expression,

11x - 6y = -1; x = 8

By substituting x = 8,

11(8) - 6y = -1

88 - 6y =-1

By subtraction property of equality,

-6y = -89

Division property of equality,

y = \frac{89}{6}

By symmetric property of equality,

\frac{89}{6} = y

7 0
3 years ago
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