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Korolek [52]
4 years ago
12

The average age of 15 students is 16 years. If teacher’s age is included the average increases by 1. Find teacher’s age. (a) 30

years (b) 32 years (c) 58 years (d) 60 years
Mathematics
2 answers:
Mrac [35]4 years ago
4 0

Answer:

Age of teacher = 32 years

Step-by-step explanation:

Average age of 15 students = 16 years

Sum of age of 15 students = 16 * 15 = 240 years

Average of age 15 students and a teacher = 17 years

Sum of age  15 students and a teacher = 17 * 16 =  272 years

Age of teacher = 272 - 240 = 32 years

Alchen [17]4 years ago
3 0

Answer:

Age of teacher = 32 years

Therefore, the correct answer is (b)

Step-by-step explanation:

We know that average is given by

Average age = Sum of ages /no. of students

We are given that the average age of 15 students is 16 years.

16 = Sum of ages/15

Sum of ages = 16×15

Sum of ages = 240

We are given that If teacher’s age is included the average increases by 1.

16 + 1 = New sum of ages/15 + 1

17 = New sum of ages/16

New sum of ages = 17×16

New sum of ages = 272

So the age of the teacher is found by

Age of teacher = New sum of ages - Sum of ages

Age of teacher = 272 - 240

Age of teacher = 32 years

Therefore, the correct answer is (b)

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A restaurant bill before tax is $15.50. How much is a 15% tip for this bill? How much money should be left for the whole bill?
ahrayia [7]

Answer:

The tip would be approximately $2.33.  The total amount of money that should be left on the bill is $17.73.

Step-by-step explanation:

To determine the tip: 15.50 times 0.15 = 2.325 ≈ 2.33

To determine the total: 15.50 plus 2.33

4 0
3 years ago
HELP I NEED THIS ANSWER ASAP
tester [92]

Answer:

10.4% or 13/125

Step-by-step explanation:

5 perfect squares in the set of numbers

13 odd numbers

(5/25) x (13/25) = 0.104

0.104 x 100 = 10.4%

i hope its right

4 0
2 years ago
I need help pls WILL GIVE BRAINLIEST
Alex73 [517]

Answer: (3,-2)

Step-by-step explanation:

-3x-7y=5\\15x+6y=33

5(-3x-7y)=5(5)\\-15x-35y=25

new system:

-15x-35y=25\\15x+6y=33

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-29y=58\\y=-2

plug in -2 for y

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4 0
2 years ago
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A random sample of 85 group leaders, supervisors, and similar personnel revealed that a person spent an average 6.5 years on the
strojnjashka [21]

Answer:

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

Step-by-step explanation:

<u><em>Step( i ):-</em></u>

<em>Given random sample size 'n' =85</em>

<em>Mean of the sample size x⁻ = 6.5 years</em>

<em>Standard deviation of Population = 1.7 years</em>

<em>Level of significance = 0.95 or 0.05</em>

<u><em>Step(ii):-</em></u>

<em>95% of confidence interval for the Population is determined by</em>

<em></em>(x^{-} - Z_{0.05} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.05} \frac{S.D}{\sqrt{n} })<em></em>

<em></em>(6.5 - 1.96\frac{1.7}{\sqrt{85} } , 6.5 + 1.96 \frac{1.7}{\sqrt{85} })<em></em>

<em>( 6.5 - 0.3614 , 6.5 + 0.3614 )</em>

<em>( 6.1386 , 6.8614)</em>

<u><em>Conclusion</em></u><em>:-</em>

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

8 0
4 years ago
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