Answer:
Step-by-step explanation:
-7x²=-448
x²=64
x=±8
<h3>
Answer:</h3>
A and C
<h3>
Step-by-step explanation:</h3>
Given:
-60x+32 = Qx+P
Find:
Which values of P and Q result in an equation with no solutions? Choose all answers that apply:
(Choice A) A Q=-60 P=60
(Choice B) B Q=32 P=60
(Choice C) C Q=-60 P=−32
(Choice D) D Q=32 P=−60
Solution:
The equation will have no solution if it reduces to ...
0 = (non-zero constant)
If we add 60x-32 to both sides, we get
0 = 60x +Qx + P-32
0 = (Q+60)x +(P-32)
The x-term must be zero, so Q+60 = 0, or Q = -60.
The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.
The appropriate answer choices are those with Q=-60 and P≠32, A and C.
Answer:
cool
Step-by-step explanation:
Answer:
Then value is 2
Step-by-step explanation:
standard of quadratic is A
+Bx+C=0
and 2 is where C is.
sorry for the bad explanation but, trust me I did this type of question in class yesterday
M = -9 ; solve for m by simplifying both sides of the equation, then isolating the varible