1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Valentin [98]
3 years ago
12

2x-8y=-24 6x+4y=68 Using elimination method

Mathematics
1 answer:
nikklg [1K]3 years ago
4 0
6(2x-8y=-24)
-2 (6x+4y=68)
12x-48y=-144
-12x-8y=-136
-56y=-280

-280÷-56=5
y=5

2x-8 (5)=-24
2x-40=-24
+40. +40
2x=16
16÷2=8
×=8


y=5
x=8
hope this helps, if needed a picture for better understanding,please comment.
You might be interested in
The measure of an angle is fifty-nine times the measure of a supplementary angle. What is the measure of each angle?
vaieri [72.5K]
So
supplementary angles are adding up to 180
lets say they are x and y
x+y=180

x is 59 times y
x=59y
subsitute

59y+y=180
add
60y=180
divide 60
y=3
subsitute
x=59y
x=59(3)
x=177

angles are
3 and 177 degrees
3 0
4 years ago
13/4% as fraction and decimal
nexus9112 [7]

Decimal: 3.25

Fraction: 13/4

4 0
3 years ago
g What is the probability of being dealt exactly three of a kind (like three kings or three 7’s, etc.) in a five card hand from
Elena L [17]

Answer: 0.02257

Step-by-step explanation:

Given : Total cards in a deck = 52

Number of ways to select any 5 cards : ^{52}C_5

Since , there are total 13 kinds of card (includes Numbers from 2 to 9 and Ace , king, queen and jack).

Of each kind , there are 4 cards.

Number of ways to select three cards in a five card hand of a single kind : ^{4}C_3\times^{48}C_2

Number of ways to select three cards in a five card hand of a exactly three of a kind : 13\times^{4}C_3\times^{48}C_2

Now , the required probability = \dfrac{13\times^{4}C_3\times^{48}C_2}{^{52}C_5}

=\dfrac{13\times4\times\dfrac{48!}{2!46!}}{\dfrac{52!}{5!47!}}\\\\\\=\dfrac{58656}{2598960}

=0.022569027611\approx0.02257

∴ The probability of being dealt exactly three of a kind (like three kings or three 7’s, etc.) in a five card hand from a deck of 52 cards= 0.02257

8 0
3 years ago
Write the equation of the following graph in intercept form.
Kobotan [32]

Answer:

A) f(x)=0.2(x+2)(x-5)

Step-by-step explanation:

The graph has x-intercepts at x=5 and x=-2, so our factors for the polynomial will be x+2 and x-5. This means we can rule out options B and D.

Our graph also has a y-intercept of y=-2 when x=0, so if we let f(x)=-2 and x=0, we can find the multiplier:

f(x)=a(x+2)(x-5)\\-2=a(0+2)(0-5)\\-2=a(2)(-5)\\-2=-10a\\\frac{1}{5}=a\\0.2=a

Thus, the correct equation is A) f(x)=0.2(x+2)(x-5)

8 0
2 years ago
Use a Venn diagram to answer the question. A survey of 180 families showed that 67 had a​ dog; 52 had a​ cat; 22 had a dog and a
Mice21 [21]

Answer:

There are 13 families had a parakeet only

Step-by-step explanation:

* Lets explain the problem

- There are 180 families

- 67 families had a dog

- 52 families had a cat

- 22 families had a dog and a cat

- 70 had neither a cat nor a​ dog, and in addition did not have a​

 parakeet

- 4 had a​ cat, a​ dog, and a parakeet (4 is a part of 22 and 22 is a part

 of 67 and 520

* We will explain the Venn-diagram

- A rectangle represent the total of the families

- Three intersected circles:

 C represented the cat

 D represented the dog

 P represented the parakeet

- The common part of the three circle had 4 families

- The common part between the circle of the cat and the circle of the

 dog only had 22 - 4 = 18 families

- The common part between the circle of the dog and the circle of the

 parakeet only had a families

- The common part between the circle of the cat and the circle of the

 parakeet only had b families

- The non-intersected part of the circle of the dog had 67 - 22 - a =

  45 - a families

  had dogs only

- The non-intersected part of the circle of the cat had 52 - 22 - b =  

  30 - b families

  had cats only

- The non-intersected part of the circle of the parakeet had c families

  had parakeets only

- The part out side the circles and inside the triangle has 70 families

- Look to the attached graph for more under stand

∵ The total of the families is 180

∴ The sum of all steps above is 180

∴ 45 - a + 18 + 4 + 30 - b + b + c + a + 70 = 180 ⇒ simplify

- (-a) will cancel (a) and (-b) will cancel (b)

∴ (45 + 18 + 4 + 30 + 70) + (-a + a) + (-b + b) + c = 180

∴ 167 + c = 180 ⇒ subtract 167 from both sides

∴ c = 180 - 167 = 13 families

* There are 13 families had a parakeet only

5 0
3 years ago
Other questions:
  • Help me plz I don’t know this question it’s math
    14·1 answer
  • The volume of this cylinder is 15,072 cubic inches, the height is 12 cubic inches What is the radius? Use ​ ≈ 3.14 and round you
    8·1 answer
  • Find the missing element in the following base-rate-percentage problem.
    15·2 answers
  • How much would $300 invested at 4% interest compounded monthly be
    15·1 answer
  • The times that a cashier spends processing individual customer’s order are independent random variables with mean 2.5 minutes an
    6·1 answer
  • 40 degree, 3x, and 4x solve for x
    7·1 answer
  • Kindest bought a new candle and the base of the candle covers an area of 19.625 square inches
    7·1 answer
  • Question 11 pts What are the image points of pre-image point (-3, 0) under the following transformations: Reflection over the y-
    10·1 answer
  • Suppose Clare labels the books at a constant speed of s books per minute. Write an equation that represents the relatinoship bet
    11·1 answer
  • What is the slope of the line that passes through the points (7, -6) and (6,-6)
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!