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LekaFEV [45]
3 years ago
14

Host A is sending Host B a large le over a TCP connection. Assume Host B has no data to send Host A. Host B will not send acknow

ledgments to Host A because Host B cannot piggyback the acknowledgments on data.a. Trueb. False
Computers and Technology
1 answer:
mestny [16]3 years ago
3 0

Answer:

False.

Explanation:

Piggybacking is an optimization that is used when both sides have to send data to each

other so that the receiver, instead of sending two packets i.e., an ACK and a data packet, it just sends one.

When the receiver (B) does not have any data to send, it will still send an ACK with the sequence number

field containing the next sequence of data it is supposed to send

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The answer is that it is true.
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1. Write programming code in C++ for school-based grading system. The program should accept the Subject and the number of studen
satela [25.4K]

In this program, I am using the school-based grading system and the program should accept the subject and the number of students.

Program approach:-

  • Using the necessary header file.
  • Using the standard I/O namespace function.
  • Define the main function.
  • Declare the variable.
  • Display enter obtain marks in 5 subjects.
  • Return the value.

Program:-

//header file

#include<iostream>

//using namespace

using namespace std;

//main method

int main()

{

//declare variable

  int j;

  float mark, sum=0, a;

//display enter obtain marks in 5 subjects

  cout<<"Enter Marks obtained in 5 Subjects: ";

  for(j=0; j<5; j++)

  {

      cin>>mark;

      sum = sum+mark;

  }

  a = sum/5;

//display grade

  cout<<"\nGrade = ";

  if(a>=91 && a<=100)

//display a1

      cout<<"a1";

  else if(a>=81 && a<91)

//display a2

      cout<<"a2";

  else if(a>=71 && a<81)

      cout<<"b1";

  else if(a>=61 && a<71)

      cout<<"b2";

  else if(a>=51 && a<61)

//display c1

      cout<<"c1";

  else if(a>=41 && a<51)

//display c2

      cout<<"c2";

  else if(a>=33 && a<41)

//display d

      cout<<"d";

  else if(a>=21 && a<33)

//display e1

      cout<<"e1";

  else if(a>=0 && a<21)

//display e2

      cout<<"e2";

  else

//display invalid

      cout<<"Invalid!";

  cout<<endl;

//return the value

  return 0;

}

Learn more grading system

brainly.com/question/24298916

7 0
3 years ago
An early attempt to force users to use less predictable passwords involved computer-supplied passwords. The passwords were eight
Sedaia [141]

Answer:

Recently, with the new and advanced hacking algorithms and affordable high-performance computers available to adversaries, the 36 character computer suggested passwords can easily be insecure.

Explanation:

The 8 length passwords generated pseudo-randomly by computers are not secure as there are new algorithms like the brute force algorithm that can dynamically obtain the passwords by looping through the password length and comparing all 36 characters to get the right one.

And also, the use of high-performance computers makes these algorithms effective

7 0
3 years ago
What critical-thinking tool is being used when asking the question, Is this information specific enough?
Murljashka [212]
Precision, specificity is related to the accuracy of the information with respect to the subject at hand. Precision is the only answer that makes sense.
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3 years ago
What did Peter and Rosemary do for a living?<br>​
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Answer:

Peter and Rosemary Grant are distinguished for their remarkable long-term studies demonstrating evolution in action in Galápagos finches. They have demonstrated how very rapid changes in body and beak size in response to changes in the food supply are driven by natural selection.

Explanation:

please

6 0
3 years ago
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