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kolbaska11 [484]
4 years ago
14

To create a formula in______, you would first click in one of the cells​

Computers and Technology
2 answers:
Pavlova-9 [17]4 years ago
5 0

Answer:excel

Explanation:

agasfer [191]4 years ago
3 0

Answer:

To create a formula in Excel  you would first click in one of the cells​

Explanation

Excel is basically calculator with advanced features. It allows the user to enter data in the form of rows and columns and enable to user to perform different kinds of calculation. It has built-in formulas and also certain conditional operation which makes the software to get the best out of it.

The user can also use the macro feature to write macro programs. Some of the common formula used are “Sum(Range), all the other basic operations like addition, multiplication, subtraction, etc.

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a_sh-v [17]

Answer: The answer to your question is B i hope this helps

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Explanation:

i hope this helps if it does have a brilliant day and have a smile

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Theresa is a certified teacher. She just had a baby and would like to stay home, but still wants to teach. Which career would be
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3 years ago
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Design a GUI program to find the weighted average of four test scores. The four test scores and their respective weights are giv
Alexus [3.1K]

<u>Answer:</u>

I am writing <em>partial code in</em> <em>c++ to calculate weighted average</em>. The weighted average should be calculated based on multiplying the test score and its <em>respective weight and finally add all the test score.</em>

<u>Explanation:</u>

<em>int arrtestscore[100];</em>

<em>int arrweight[100];</em>

<em>int n;</em>

<em>double weightedavg;</em>

<em>cout<<”Enter the number of test score for which weighted average needs to be calculated”;</em>

<em>cin>>n;</em>

<em>for(int x = 0; x <n;x++)</em>

<em>{</em>

<em> cout<<”Enter test score :” + (x+1) ;</em>

<em> cin>>arrtestscore[x];</em>

<em> count<<”Enter the respective weight:”;</em>

<em> cin>>arrweight[x];</em>

<em>}</em>

<em>for (int i=0; i<n;i++)</em>

<em>{</em>

<em> weightedavg = weightedavg + (arrtestscore[i] * arrweight[i])</em>

<em>}</em>

<em>cout<<”weighted average = “ <<weightedavg; </em>

3 0
3 years ago
How many survey monkey devices are you allowed to have for each user
svp [43]

Answer:

(Hope this helps can I pls have brainlist (crown) ☺️)

Explanation:

Per account, you can verify up to two devices at once. The removal of a recognized device and the addition of a new one counts against your removal limit. You can only log in from the two most recent confirmed devices if you hit the removal limit.

3 0
3 years ago
Python
andreyandreev [35.5K]

Answer:

<h2>1)   </h2>

h = 19  # h is already assigned a positive integer value 19

i = 1  # used to calculate perfect square

q = 0   # stores the sum of the perfect squares

while q < h:  

# this loop executes until value of number of perfect squares is less than h

   q = q + (i*i)  # to calculate the sum of perfect squares

   i = i + 1  # increments i by 1 at every iteration

print(q) # displays the sum of perfect squares

Output:

30

Explanation:

Here we see that the sum of the perfect square is printed in the output i.e. 30. If we want to assign value 4 to q then we should alter the code as  following:  

h = 19

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   q = q + 1

   i = i + 1  

print(q)  

If you want to take input from the user and also display the perfect squares in output you can use the following code:

h = int(input('Enter the value of h: ')) #takes value of h from user

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   print(i*i) #displays the perfect squares of h

   q = q + 1

   i = i + 1    

print(sum_of_ps)   #displays sum of perfect squares

print(q) #displays number of perfect squares whose value is less than h

Output:

1

4

9

16

30

4

<h2>2)</h2>

# k and m are already assigned positive integers 10 and 40

k = 10  

m = 40  

i = 1  # i is initialized to 1

q = 0  # q stores the number of perfect squares between k and m

while i*i < m:  # loop computes perfect square of numbers between k and m

   if i*i > k:          

       q = q + 1  # counts the number of perfect squares

   i = i + 1  #increments the value of i at each iteration

print (q) # prints the no of perfect squares between k and m

If you want to display the perfect squares too use , add print(i*i) statement after if statement  if i*i > k:        

Output:

3

<h2>3)</h2>

def Fibonacci(n):  # method Fibonacci which has an integer parameter n

   if n <= 1:  # if the value of n is less than or equals to 1

       result = n  # stores the value of n into result

   elif n > 1:  # else if the value of n is greater than 1

       result = Fibonacci(n-1) + Fibonacci(n-2)  

# calls Fibonacci method recursively to associate nth value of Fibonacci #sequence with variable result

   return result     #returns the final value stored in result variable

print(Fibonacci(8))

#calls Fibonacci function and passes value 8 to it

Output:

21

8 0
3 years ago
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