Question

YP=+8+10+12+...+ 106 and Q=2+4+6+8+ ... 104 are sums of arithmetic sequences, determine which is greater, Por Q, and by how much

Answer 1

Answer:

P is greater by 94.

Step-by-step explanation:

P =                   8 + 10 + 12 + ..... + 102 + 104 + 106

Q= 2 + 4 + 6 + 8 + 10 + 12 + ......+ 102 + 104

The terms from 8 + 10 + ... + 104 are the same on both P and Q.

Therefore, the different terms are the 106 in P and the 2 + 4 + 6 in Q.

Clearly 106 > 2 + 4 + 6, so P is greater.

To know by how much we would subtract 2 + 4 + 6 = 12 from 106.

106 - 12 = 94.