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inna [77]
3 years ago
15

At 5% commision, an agent received rs.32,500 by selling a second-hand car. At what price did he/she sell tha car?

Mathematics
1 answer:
lara [203]3 years ago
8 0
<h2><em>Answer:</em></h2><h2><em>Rs </em><em>6</em><em>5</em><em>0</em><em>0</em><em>0</em><em>0</em></h2>

<em>Solution</em><em>,</em>

<em>Let </em><em>the </em><em>price </em><em>of </em><em>car </em><em>be </em><em>X.</em>

<em>Rate(</em><em>R)</em><em>=</em><em>5</em><em>%</em>

<em>Here</em><em>,</em>

<em>Commission</em><em> </em><em>%</em><em> </em><em>of </em><em>price </em><em>of </em><em>car=</em><em>3</em><em>2</em><em>5</em><em>0</em><em>0</em>

<em>or,</em><em>5</em><em>%</em><em> </em><em>of </em><em>X=</em><em>3</em><em>2</em><em>5</em><em>0</em><em>0</em>

<em>or,</em><em>5</em><em>/</em><em>100*</em><em>X=</em><em>3</em><em>2</em><em>5</em><em>0</em><em>0</em>

<em>or,</em><em>X=</em><em>3</em><em>2</em><em>5</em><em>0</em><em>0</em><em>*</em><em>2</em><em>0</em>

<em>X=</em><em>Rs </em><em>6</em><em>5</em><em>0</em><em>0</em><em>0</em><em>0</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> </em><em>assignment.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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Simplify. Can you explain it also?
Doss [256]

Answer:

The answer is

<h2>\frac{3c}{4e}</h2>

Step-by-step explanation:

<h3>\frac{9 {c}^{3}d {e}^{2}  }{12 {c}^{2} d {e}^{3} }</h3>

To solve the fraction reduce the fraction with d

That's we have

<h2>\frac{9 {c}^{3}  {e}^{2} }{12 {c}^{2} {e}^{3}  }</h2>

Next simplify the expression using the rules of indices to simplify the letters in the fraction

<u>For c </u>

Since they are dividing we subtract the exponents

We have

<h2>{c}^{3}  \div  {c}^{2}  =  {c}^{3 - 2}  = c^{1}  = c</h2>

<u>For </u><u>e</u>

<h2>e^{2}  \div  {e}^{3}  = e^{2 - 3}  =  {e}^{ - 1}  =  \frac{1}{e}</h2>

Substituting them into the expression we have

<h2>\frac{9c}{12e}</h2>

Reduce the fraction by 3

We have the final answer as

<h2>\frac{3c}{4e}</h2>

Hope this helps you

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